fan and medal! PArt A: the sun produces 3.9-10^33 ergs of radiant energy per second. how many ergs of radiant energy does the sun produce in 2.45 - 10^5 seconds? PArt B: which is the more reasonable MEASUREMENT OF THE DISTANCE BETWEEN THE TRACKS on a DVD: 7.4-10^-4mm or 7.4-10^4mm?

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fan and medal! PArt A: the sun produces 3.9-10^33 ergs of radiant energy per second. how many ergs of radiant energy does the sun produce in 2.45 - 10^5 seconds? PArt B: which is the more reasonable MEASUREMENT OF THE DISTANCE BETWEEN THE TRACKS on a DVD: 7.4-10^-4mm or 7.4-10^4mm?

Pre-Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Well if you've got 3.9x10^33 erg per second and 2.45x10^5 seconds, then you just multiply the two numbers together to get the total amount of radiant energy. For the second bit, 7.4x10^-4mm is a very very small distance, and 7.4x10^4mm is 74 metres... can you guess which one is the right answer? :P
ok um for the first part don't I add them instead?
Nope. As a simpler example, say you have a car travelling at 10 metres per second, and it travels for 5 seconds. How far does the car travel? 5 x 10 = 50 metres. It's the same principle with this question.

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oh ok thanks! :)
No problem :P

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