Evaluate the expression below when x = 1.
2x2 − 5
x + 9
 anonymous
Evaluate the expression below when x = 1.
2x2 − 5
x + 9
 schrodinger
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 anonymous
somebody help me please
 anonymous
please help me and sheppard18 these questions is what we are depending on to graduate
 anonymous
??
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 anonymous
??
 anonymous
hello??
 Nnesha
replace x by 1
 anonymous
is that the answer
 Nnesha
nope
 anonymous
whats the answer
 confluxepic
Just substitute it.
 Nnesha
\[2(1)^2 5\]
substitute value and then solve !
 anonymous
i dont know how to substitute because we have never ever had a half decent math teacher
 Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha
\[2(1)^2 5\]
substitute value and then solve !
\(\color{blue}{\text{End of Quote}}\)
like this just replace x and plug 1 now solve
what is square of (1) ?
 Nnesha
(1)^2 is same as 1 times 1 = what ?
 anonymous
i dont know what the answer is
 confluxepic
For example x=12.
3(x)+2=y
3(12)+2=y <
36+2=y 
38=y 

See how I substituted x as 12 to solve the example equation? 
 Nnesha
what is 1 times 1 = ??
 confluxepic
Arrow line messed up.
 anonymous
1?
 Nnesha
negative times negative = positive
negative times positive = negative
so negative 1 times negative 1 = ?
 Nnesha
@sheppard18 what do you think ?
1 times 1 = ??
 anonymous
1?
 Nnesha
yes right
 anonymous
1 is not a choice
 Nnesha
\[2(1)^2 5\]
\[2(1)5 =what ??\]
 Nnesha
i didn't say one is the answer
 anonymous
7/8, 3/8, 1/8, 1 theses are the choices we have
 anonymous
3?
 confluxepic
Example:
x+2=y
You know that x is 1 but you need to find out y.
So you put \(\color{red}{x~as~1}\) in the equation.
\(\color{red}{(1)}\)+2=y.
1+2=3 so y=3.
Get it?
 Nnesha
yes that's right!
remember PEMDAs rule
Parentheses
exponent
MD) MULTIPLY OR DIVIDE
AS ) ADD OR SUBTRACT
 anonymous
please just tell me the answer
 anonymous
were from tug valley we dont know much
 Nnesha
you have to learn in order to know something
 anonymous
are teacher does nothing but sleep in class
 anonymous
and calls the office on our class because our class is so mean
 Nnesha
alright thanks for joining os
here we will teach u
no direct answers!!
 anonymous
well how do i do it
 Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @estepp33
3?
\(\color{blue}{\text{End of Quote}}\)
yes right
 anonymous
what about 3
 Nnesha
substitute given x value which is 1 \[\huge\rm 2(1)^2 5 \]
take square of 1 which is 1 (1 times 1 = 1)
\[2(1)5 = ???\]
 anonymous
that comes out to be 3 what do we do with the 3
 Nnesha
that's the answer of first one
 Nnesha
i guess your question is \[\frac{ 2x^2 5 }{ x+9 }\]
right it's a fraction ?
 anonymous
it will be a fraction or a whole numbner
 anonymous
yes its a fraction i need help with the bottom now
 Nnesha
so why you didn't tell me ??
use */* for fraction so we know it's a fraction
 Nnesha
i thought those are 2 different expression
 Nnesha
\[\huge\rm \frac{ 2\color{blue}{x^2} 5 }{ \color{blue}{x}+9 }\]
just like we did before
replace x by 1
 anonymous
would the answer be 3/8
 Nnesha
that's right
 anonymous
i got 8
 Nnesha
yes the denominator is 8
 anonymous
can u help me with this question
The simplest form of the expression 4m−17m2−16+3m−11m2−16 has in the numerator and in the denominator.
 Nnesha
and how do i know what is in the numerator and what is in the denominator
use the equation and type ur question
 anonymous
i dont know
 Nnesha
what ?
 Nnesha
\[\huge\rm 4m−17m^2−16+3m−11m^2−16\]
like this ?
 anonymous
4m17/m^216+3m11/m^216
 anonymous
that is the fraction ^
 anonymous
4m17/m^2 this is the fraction
 Nnesha
\[\huge\rm \frac{ 4m17 }{ m^2 } \frac{ 16+3m11 }{ m^2 16 }\] like this ?
 anonymous
yea
 anonymous
m^216 on both bottom sides
 Nnesha
\[\huge\rm \frac{ 4m17 }{ m^2 16} \frac{ 16+3m11 }{ m^2 16 }\]
looks good ?
 anonymous
yes
 anonymous
no
 Nnesha
alright type your question please
 anonymous
4m17/m^216 + 3m11/m^216
 anonymous
the minus sign should be plus and the 16 on top on the right shouldnt be there
 Nnesha
\[\huge\rm \frac{ 4m17 }{ m^2 16} +\frac{ 3m11 }{ m^2 16 }\]
find common denominator?
what is common denominator ?
 anonymous
16
 anonymous
16?
 anonymous
??
 Nnesha
1not just 16
m^2 16 should be together \[\huge\rm \frac{ }{m^2 16 }\]
so m^2 and 16= common denominator
 anonymous
ok what do i do
 Nnesha
now bec denominator of both fraction are same as common denominator so just carry down the value of numerator \[\huge\rm \frac{ 4m17+3m11 }{ m^2 16 }\]
now combine like terms
4m17+3m 11= what ?
 anonymous
21
 Nnesha
how did yo uget 21 ?
 anonymous
i done 417+311
 Nnesha
what are LIKe terms ?
 Nnesha
you can't combine 4m with 17 bec there are not the same
 anonymous
3 and 4
 Nnesha
add coefficient of same variable
yes right 3m and 4m combine them
 Nnesha
3m+4m =what ?
1711= ?
 anonymous
7 and 28
 anonymous
??
 Nnesha
\[ \huge\rm \frac{ 7m 28 }{ m^2 16 }\]
now factor 7m28 what is common factor ?
 Nnesha
nd apply difference of square for the denominator part \[\rm a^2  b^2 = (a+b)(ab)\]
 anonymous
what do i do with that
 Nnesha
alright first factor the numerator
7m28 what is common factor ?
 anonymous
is it m+4
 anonymous
??
 Nnesha
for which one ?
 anonymous
the right one
 Nnesha
alright 7m28 what is common in these both terms ??
 anonymous
i got to go im going home
 anonymous
thanks for the help
 anonymous
we have drop down menues
 anonymous
menu
 Nnesha
7m 28
7 is common so take it out \[7( ????)\]
now divide both terms by 7 and write your answer in the parenthses
 anonymous
is the answer m+4
 Nnesha
nope not just m+4
 Nnesha
m^2 16 = w hat ?
 anonymous
?
 Nnesha
m^2 16 what are factor of this equation
 anonymous
it said error
 Nnesha
apply difference of square method \[\huge\rm a^2 b^2 = (a+b)(ab)\]
 Nnesha
what ? who said error ?
 Nnesha
apply difference of square method \[a^2 b^2 =(a+b)(ab)\]
 anonymous
the caa
 anonymous
calculator
 Nnesha
don't use calculator
take square root of first term and 2nd term dw:1434382762154:dw
 anonymous
?
 Nnesha
Take square root of first term and take square root of 2nd term
write ur answer in both parentheses (sqrt of 1st term PLUS sqrt of 2nd term) (sqrt of 1st term  sqrt of 2nd term )
example dw:1434382868450:dw
 anonymous
(m+1) (26)
 Nnesha
that's an example
m^2  16 = what ??
 anonymous
idk
 Nnesha
difference of square method have to when both terms are perfect square root and there should be negative sign
for example x^2  36
1st term =x^2
2nd term =36
square root of first term is =x
square root of 2nd term is = 6
now write these in parenthesesdw:1434383072396:dw
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