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anonymous

  • one year ago

5(x + 2) greater than or equal to 7x + 2(x − 1) I need help

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  1. alekos
    • one year ago
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    so I guess you need to solve for x, is that right?

  2. anonymous
    • one year ago
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    yes can you please help me?

  3. alekos
    • one year ago
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    \[5(x+2) \ge 7x+2(x-1)\]

  4. alekos
    • one year ago
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    so lets start with the LHS and expand

  5. anonymous
    • one year ago
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    ok so we distribute first right

  6. alekos
    • one year ago
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    yep

  7. alekos
    • one year ago
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    over to you

  8. anonymous
    • one year ago
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    so it will be 5x and 2x

  9. anonymous
    • one year ago
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    5(x + 2) greater than or equal to 7x + 2(x − 1) 5x + 10

  10. anonymous
    • one year ago
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    7x + 2x-2

  11. anonymous
    • one year ago
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    5x +10 < 9x-2

  12. alekos
    • one year ago
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    NO \[5x+10\ge9x-2\]

  13. alekos
    • one year ago
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    Now you'll need to get x's on the left and constants on the right

  14. anonymous
    • one year ago
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    @smart103 What was the correct answer?

  15. alekos
    • one year ago
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    Next step is \[5x-9x \ge -2-10\]

  16. alekos
    • one year ago
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    then we have \[-4x \ge-12\]

  17. alekos
    • one year ago
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    multiply both sides by -1 \[4x \le12\]

  18. alekos
    • one year ago
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    finally divide both sides by 4 \[x \le3\]

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