anonymous
  • anonymous
5(x + 2) greater than or equal to 7x + 2(x − 1) I need help
Algebra
jamiebookeater
  • jamiebookeater
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alekos
  • alekos
so I guess you need to solve for x, is that right?
anonymous
  • anonymous
yes can you please help me?
alekos
  • alekos
\[5(x+2) \ge 7x+2(x-1)\]

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alekos
  • alekos
so lets start with the LHS and expand
anonymous
  • anonymous
ok so we distribute first right
alekos
  • alekos
yep
alekos
  • alekos
over to you
anonymous
  • anonymous
so it will be 5x and 2x
anonymous
  • anonymous
5(x + 2) greater than or equal to 7x + 2(x − 1) 5x + 10
anonymous
  • anonymous
7x + 2x-2
anonymous
  • anonymous
5x +10 < 9x-2
alekos
  • alekos
NO \[5x+10\ge9x-2\]
alekos
  • alekos
Now you'll need to get x's on the left and constants on the right
anonymous
  • anonymous
@smart103 What was the correct answer?
alekos
  • alekos
Next step is \[5x-9x \ge -2-10\]
alekos
  • alekos
then we have \[-4x \ge-12\]
alekos
  • alekos
multiply both sides by -1 \[4x \le12\]
alekos
  • alekos
finally divide both sides by 4 \[x \le3\]

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