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anonymous

  • one year ago

Use substitution method to solve for y=3/2x-1 y=4x+4 The correct answer is (-2,-4) but I ended up with 8/3x=-5 ....

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  1. anonymous
    • one year ago
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    Is the second equation supposed to say \(y=4x+4\)?

  2. anonymous
    • one year ago
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    Yes

  3. anonymous
    • one year ago
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    Okay. It doesn't matter which equation you substitute into which, so I'll just take the first one. \[y=\frac{3}{2}x-1\] You can solve for \(x\), or leave it alone. I'll leave it alone. Plug it into the second equation: \[y=4x+4~~\implies~~\frac{3}{2}x-1=4x+4\] Good so far?

  4. anonymous
    • one year ago
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    So far so good

  5. anonymous
    • one year ago
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    Okay, now you solve for \(x\): \[\begin{align*} \frac{3}{2}x-1&=4x+4\\ \frac{3}{2}x-4x&=4+1\\ \left(\frac{3}{2}-4\right)x&=5\\ \left(\frac{3}{2}-\frac{8}{2}\right)x&=5\\ -\frac{5}{2}x&=5\\ x&=-\frac{2}{5}\times5\\ x&=-2 \end{align*}\] You can easily find \(y\) now.

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