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Trig question please help asap! Fan and medal! :) Simplify the trigonometric expression. cos^2 (theta) ----------- 1 - sin (theta) A. sin (theta) B. 1 + sin (theta) C. 1 - sin (theta) D. 1 - sin (theta)/sin (theta)

Mathematics
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what's another way of writing \[\cos ^{2}\theta\]
cos * cos (theta)?

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Other answers:

no. use \[\sin ^{2}\theta + \cos ^{2}\theta = 1\]
so \[\cos ^{2}\theta = ?\]
1 - sin^2 (theta)?
yes thats it, so we now have \[\frac{ 1-\sin ^{2}\theta }{1-\sin \theta}\]
can you see what we need to do next?
so it would be A?
no not at all
the numerator can be expressed as the product of two factors
oh oops
any ideas?
I'm thinking that it's either C or D
you're just guessing and not answering my question
i'm going
i'm going with my gut is what i'm doing.
why are you going?
thats not how you do maths
product of two factors. what do you think?
Don't go off in a frenzy if I get it wrong but would it (the numerator) be (1 - sin)(sin (theta))?
you're a funny girl. let x = sin(theta) so we have 1 - x^2
and 1 - x^2 = (1-x)(1+x)
i'm just doing the numerator only
do you follow?
yes so far
so the numerator is (1-x)(1+x) and the denominator is 1-x
what can we do now?
so written all out (what you just wrote, just to clarify) it would look like {(1-x)(1+x)}/(1-x)? would the 1-x cancel out?
excellent thats right!
and we have 1+x substitute back x = sin(theta)
and the answer is?
B
well done. I hope you now understand how its done?
yes much better :) ty!!!!!!!!!!!!!
your welcome

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