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what's another way of writing \[\cos ^{2}\theta\]

cos * cos (theta)?

no. use \[\sin ^{2}\theta + \cos ^{2}\theta = 1\]

so \[\cos ^{2}\theta = ?\]

1 - sin^2 (theta)?

yes thats it, so we now have
\[\frac{ 1-\sin ^{2}\theta }{1-\sin \theta}\]

can you see what we need to do next?

so it would be A?

no not at all

the numerator can be expressed as the product of two factors

oh oops

any ideas?

I'm thinking that it's either C or D

you're just guessing and not answering my question

i'm going

i'm going with my gut is what i'm doing.

why are you going?

thats not how you do maths

product of two factors. what do you think?

Don't go off in a frenzy if I get it wrong but would it (the numerator) be (1 - sin)(sin (theta))?

you're a funny girl. let x = sin(theta)
so we have 1 - x^2

and 1 - x^2 = (1-x)(1+x)

i'm just doing the numerator only

do you follow?

yes so far

so the numerator is (1-x)(1+x)
and the denominator is 1-x

what can we do now?

excellent thats right!

and we have 1+x
substitute back x = sin(theta)

and the answer is?

B

well done. I hope you now understand how its done?

yes much better :) ty!!!!!!!!!!!!!

your welcome