The girder of a train bridge is in parabolic form. The girder is supported with a strong beam of iron. The equations of the parabolic girder and iron beam are given. Find the points at which the iron beam joins the parabolic path. (6, 7) and (0, 7) (6, 7) and (0, -7) (6, -7) and (0, 7) (-6, -7) and (6, 7)

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The girder of a train bridge is in parabolic form. The girder is supported with a strong beam of iron. The equations of the parabolic girder and iron beam are given. Find the points at which the iron beam joins the parabolic path. (6, 7) and (0, 7) (6, 7) and (0, -7) (6, -7) and (0, 7) (-6, -7) and (6, 7)

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Other answers:

Factor the quadratic
i did
i got x= 7 and a =1
y=1
help?
im not good at this but i'll try c:
ok
i factored it and got (-x-1)(x+7)
@jordanawest22 what did u get?
thats what i got @Godlovesme

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