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I'm not personally, but if you asked your question, I'm sure someone would be able to help you.

i need help with this

oh are you not in 10th grade?

question #1a
the requested inequality is:
\[ \Large - 12{x^2} + 960x \geqslant 18000\]

thank you but i need help pn 3a 3b

@Michele_Laino could you help me

question #3a
the requested inequality is:
\[\Large - 12{x^2} + 960x \leqslant 18432\]

so thats the inequality?

would the answer be

ok thank you so for 3a where as it says write an inequailty when she will not be taxes will it be >/ 50 because on the graph

ok!

im asking is that correct?

the requested inequality is
\[\Large x \geqslant 48\]

ok thank you. could you help me on more or are you stressed out?

I can help you! :)

ok thankyou here are the other ones

question #4a
the requested inequality is:
\[\Large - 12{x^2} + 960x \leqslant 14400\]

how would you do b?

here is the graph:

THANK YOU ! so i would shade below the graph correct?

yes! correct!

so the solution is:
\[\Large x \geqslant 60\]

wait so how would x> 60 belong in the equation ?

ok thank you what about these

question #5
as we can see from the drawing below, our solution is:
\[x \leqslant 1 \cup x \geqslant 5\]

what does u stand for?

it is the union of sets

do i put and or or ? or u

that writing is equivalent to this one:
\[( - \infty ,1] \cup [5, + \infty )\]
you can put "or"

Question #6
as we can see from the drawing below, our solution is:
\[ - 1 \leqslant x \leqslant 5\]

x=3,1?

ok!

so we can write the solution as an inequality below:
\[1 < x < 3\]

shaded to the left?

it is:
|dw:1434396507609:dw|
and x=1 , x=3 don't belong to the solution interval

1.93?

are you sure?

please wait a moment

ya...

I got:
x=3, and x=-4/3
so our solution is:
\[x < - 4/3,\;x > 3\]
|dw:1434399244525:dw|

x=3, and x=-4/3 don't belong to the solution interval

i got x>/ -3?

ok thank you for 1d on paula peaches i got 30

the inequality:
\[{x^2} + 6x + 9 \geqslant 0\] is always true, and the equal sign holds, when x=-3

30/60

more precisely:
60

for 2b i got x would equal 50, 30 and c im a little lost on thats the last two

there we have to solve this inequality:
\[ - 12{x^2} + 960x \geqslant 18000\]

which, after a simplification, becomes:
\[{x^2} - 80x + 1500 \leqslant 0\]

now the roots of the associated quadratic equation:
\[{x^2} - 80x + 1500 = 0\]
are:
x=50 and x=30

so the requested solution is:
\[30 \leqslant x \leqslant 50\]

so we have the subsequent graph:
|dw:1434401181442:dw|

thank you so much for the help you answered my questions fully