anonymous
  • anonymous
what would be the pressure of a given mass of a gas, if its volume and temperature are doubled ............. ?
Physics
chestercat
  • chestercat
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anonymous
  • anonymous
Considering an ideal gas, you can use the relation: \[PV=nRT\] taking \(n\) (the nomber of molecules) as a constant, since the mass is not changing, and since \(R\) is the ideal gas constant we get: \[\frac{PV}{T}=constant\] so if you double the volume and temperature you must get the same constant value for that expression, and then: \[\frac{P_1V_1}{T_1}=\frac{P_2(2V_1)}{2T_1}\] what is the relation between the new pressure \(P_2\) and \(P_1\) ??
anonymous
  • anonymous
he wants complement one word
anonymous
  • anonymous
consentration

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anonymous
  • anonymous
concentration !
anonymous
  • anonymous
that word is contained in the response to my question: what is the relation between the new pressure \(P_2\) and \(P_1\) ?? What happens if we cancel out the 2's in the right hand side?
anonymous
  • anonymous
yes concentration

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