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anonymous

  • one year ago

what would be the pressure of a given mass of a gas, if its volume and temperature are doubled ............. ?

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  1. JoannaBlackwelder
    • one year ago
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    P1V1/T1=P2V2/T2 when mass is constant.

  2. JoannaBlackwelder
    • one year ago
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    What happens when we sub in 2V1 for V2

  3. JoannaBlackwelder
    • one year ago
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    And 2T1 for T2?

  4. anonymous
    • one year ago
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    He wants to complement the question one word

  5. JoannaBlackwelder
    • one year ago
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    Ok, we are getting there.

  6. anonymous
    • one year ago
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    so the answer : mass is constant.?

  7. JoannaBlackwelder
    • one year ago
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    No, that is an assumption, since we aren't told how it will change.

  8. JoannaBlackwelder
    • one year ago
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    Do you see how when the volume is doubled, that would be 2 times the original volume?

  9. anonymous
    • one year ago
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    yes

  10. JoannaBlackwelder
    • one year ago
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    Ok, cool. And the same for temp?

  11. anonymous
    • one year ago
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    yup

  12. JoannaBlackwelder
    • one year ago
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    Ok, so, can you plug those into the equation?

  13. anonymous
    • one year ago
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    P1V1/T1=P2V2/T2

  14. JoannaBlackwelder
    • one year ago
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    That is the original equation. Can you plug in the other expressions we came up with?

  15. anonymous
    • one year ago
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    I don't understand sorry

  16. JoannaBlackwelder
    • one year ago
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    It's cool. So, since V2 can be represented by 2V1, P1V1/T1=P2(2V1)/T2

  17. JoannaBlackwelder
    • one year ago
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    Does that step make sense?

  18. anonymous
    • one year ago
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    yes

  19. JoannaBlackwelder
    • one year ago
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    :-) Can you try plugging in the expression for T2?

  20. anonymous
    • one year ago
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    T2= P1V2T1/P2V1

  21. JoannaBlackwelder
    • one year ago
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    Not solve, substitute.

  22. Melodious
    • one year ago
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    joanna

  23. anonymous
    • one year ago
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    :c

  24. Melodious
    • one year ago
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    that question i didnt understand

  25. Melodious
    • one year ago
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    :c

  26. anonymous
    • one year ago
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    He wants to complement the question one word

  27. Melodious
    • one year ago
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    ur a boy?

  28. anonymous
    • one year ago
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    yup

  29. JoannaBlackwelder
    • one year ago
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    P1V1/T1=P2(2V1)/(2T1) Do you see how I subbed that in?

  30. JoannaBlackwelder
    • one year ago
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    Since T2 is 2T1

  31. anonymous
    • one year ago
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    oh, yeah

  32. JoannaBlackwelder
    • one year ago
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    :-) So, can you simplify?

  33. anonymous
    • one year ago
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    no :c

  34. anonymous
    • one year ago
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    I can't :c

  35. Melodious
    • one year ago
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    which grade chemistry ur talking about?

  36. Melodious
    • one year ago
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    pls say

  37. JoannaBlackwelder
    • one year ago
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    |dw:1434392830978:dw|

  38. JoannaBlackwelder
    • one year ago
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    I meant |dw:1434392864965:dw|

  39. Melodious
    • one year ago
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    nice idea jo!!!

  40. JoannaBlackwelder
    • one year ago
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    Thanks. :-) The 2's cancel|dw:1434392913865:dw|

  41. JoannaBlackwelder
    • one year ago
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    Does that make sense?

  42. Melodious
    • one year ago
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    yeah

  43. Melodious
    • one year ago
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    but which grade chemistry is this?????????

  44. JoannaBlackwelder
    • one year ago
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    That's good, @Melodious but I was asking @soso707

  45. anonymous
    • one year ago
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    yes @JoannaBlackwelder

  46. Melodious
    • one year ago
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    pls say which grade

  47. JoannaBlackwelder
    • one year ago
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    Great! So we are to |dw:1434393062140:dw|

  48. JoannaBlackwelder
    • one year ago
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    Any ideas from here?

  49. Melodious
    • one year ago
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    nope i think

  50. anonymous
    • one year ago
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    no complete

  51. JoannaBlackwelder
    • one year ago
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    Please give it a shot. It is against policy to just give you the answers and we are mighty close to the answer.

  52. anonymous
    • one year ago
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    Gay-Lussac's law ?

  53. JoannaBlackwelder
    • one year ago
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    No, we just need to simplify what we have so far.

  54. JoannaBlackwelder
    • one year ago
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    Using algebra

  55. anonymous
    • one year ago
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    |dw:1434393687091:dw|

  56. JoannaBlackwelder
    • one year ago
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    Where did the equals sign go?

  57. anonymous
    • one year ago
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    We unite place.

  58. JoannaBlackwelder
    • one year ago
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    I don't understand what you mean.

  59. anonymous
    • one year ago
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    I mean T1

  60. JoannaBlackwelder
    • one year ago
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    I still don't understand what you are trying to say. Can you show me?

  61. anonymous
    • one year ago
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    |dw:1434394032412:dw|

  62. JoannaBlackwelder
    • one year ago
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    Hm, no, the equals sign can't just disappear.

  63. anonymous
    • one year ago
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    so wahat ?

  64. JoannaBlackwelder
    • one year ago
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    If we multiply both sides by T1, what happens? |dw:1434394220901:dw|

  65. anonymous
    • one year ago
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    aha

  66. JoannaBlackwelder
    • one year ago
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    :-)

  67. anonymous
    • one year ago
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    There will be less pressure?

  68. JoannaBlackwelder
    • one year ago
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    How do you get that?

  69. anonymous
    • one year ago
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    just I think that

  70. JoannaBlackwelder
    • one year ago
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    No, that's not what I get.|dw:1434395143188:dw|

  71. JoannaBlackwelder
    • one year ago
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    |dw:1434395174203:dw|

  72. anonymous
    • one year ago
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    yeah

  73. JoannaBlackwelder
    • one year ago
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    Is there anything else that can cancel?

  74. anonymous
    • one year ago
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    I think, no

  75. anonymous
    • one year ago
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    or V1?

  76. JoannaBlackwelder
    • one year ago
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    Right, great!

  77. JoannaBlackwelder
    • one year ago
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    So, what does that leave us with?

  78. anonymous
    • one year ago
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    P1=P2

  79. JoannaBlackwelder
    • one year ago
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    :-)

  80. anonymous
    • one year ago
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    so what now ?

  81. JoannaBlackwelder
    • one year ago
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    What do you think that means?

  82. anonymous
    • one year ago
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    that the pressure same ?

  83. JoannaBlackwelder
    • one year ago
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    Yep

  84. anonymous
    • one year ago
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    so : what would be the pressure of a given mass of a gas, if its volume and temperature are doubled same pressure ?

  85. JoannaBlackwelder
    • one year ago
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    Yep, or "pressure is constant"

  86. anonymous
    • one year ago
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    thanks a lot @JoannaBlackwelder :)

  87. JoannaBlackwelder
    • one year ago
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    You're very welcome :-)

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