what would be the pressure of a given mass of a gas, if its volume and temperature are doubled ............. ?

- anonymous

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- schrodinger

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- JoannaBlackwelder

P1V1/T1=P2V2/T2 when mass is constant.

- JoannaBlackwelder

What happens when we sub in 2V1 for V2

- JoannaBlackwelder

And 2T1 for T2?

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## More answers

- anonymous

He wants to complement the question one word

- JoannaBlackwelder

Ok, we are getting there.

- anonymous

so the answer : mass is constant.?

- JoannaBlackwelder

No, that is an assumption, since we aren't told how it will change.

- JoannaBlackwelder

Do you see how when the volume is doubled, that would be 2 times the original volume?

- anonymous

yes

- JoannaBlackwelder

Ok, cool. And the same for temp?

- anonymous

yup

- JoannaBlackwelder

Ok, so, can you plug those into the equation?

- anonymous

P1V1/T1=P2V2/T2

- JoannaBlackwelder

That is the original equation. Can you plug in the other expressions we came up with?

- anonymous

I don't understand sorry

- JoannaBlackwelder

It's cool. So, since V2 can be represented by 2V1,
P1V1/T1=P2(2V1)/T2

- JoannaBlackwelder

Does that step make sense?

- anonymous

yes

- JoannaBlackwelder

:-) Can you try plugging in the expression for T2?

- anonymous

T2= P1V2T1/P2V1

- JoannaBlackwelder

Not solve, substitute.

- Melodious

joanna

- anonymous

:c

- Melodious

that question i didnt understand

- Melodious

:c

- anonymous

He wants to complement the question one word

- Melodious

ur a boy?

- anonymous

yup

- JoannaBlackwelder

P1V1/T1=P2(2V1)/(2T1)
Do you see how I subbed that in?

- JoannaBlackwelder

Since T2 is 2T1

- anonymous

oh, yeah

- JoannaBlackwelder

:-) So, can you simplify?

- anonymous

no :c

- anonymous

I can't :c

- Melodious

which grade chemistry ur talking about?

- Melodious

pls say

- JoannaBlackwelder

|dw:1434392830978:dw|

- JoannaBlackwelder

I meant |dw:1434392864965:dw|

- Melodious

nice idea jo!!!

- JoannaBlackwelder

Thanks. :-) The 2's cancel|dw:1434392913865:dw|

- JoannaBlackwelder

Does that make sense?

- Melodious

yeah

- Melodious

but which grade chemistry is this?????????

- JoannaBlackwelder

That's good, @Melodious but I was asking @soso707

- anonymous

yes @JoannaBlackwelder

- Melodious

pls say which grade

- JoannaBlackwelder

Great! So we are to |dw:1434393062140:dw|

- JoannaBlackwelder

Any ideas from here?

- Melodious

nope i think

- anonymous

no complete

- JoannaBlackwelder

Please give it a shot. It is against policy to just give you the answers and we are mighty close to the answer.

- anonymous

Gay-Lussac's law ?

- JoannaBlackwelder

No, we just need to simplify what we have so far.

- JoannaBlackwelder

Using algebra

- anonymous

|dw:1434393687091:dw|

- JoannaBlackwelder

Where did the equals sign go?

- anonymous

We unite place.

- JoannaBlackwelder

I don't understand what you mean.

- anonymous

I mean T1

- JoannaBlackwelder

I still don't understand what you are trying to say. Can you show me?

- anonymous

|dw:1434394032412:dw|

- JoannaBlackwelder

Hm, no, the equals sign can't just disappear.

- anonymous

so wahat ?

- JoannaBlackwelder

If we multiply both sides by T1, what happens?
|dw:1434394220901:dw|

- anonymous

aha

- JoannaBlackwelder

:-)

- anonymous

There will be less pressure?

- JoannaBlackwelder

How do you get that?

- anonymous

just I think that

- JoannaBlackwelder

No, that's not what I get.|dw:1434395143188:dw|

- JoannaBlackwelder

|dw:1434395174203:dw|

- anonymous

yeah

- JoannaBlackwelder

Is there anything else that can cancel?

- anonymous

I think, no

- anonymous

or V1?

- JoannaBlackwelder

Right, great!

- JoannaBlackwelder

So, what does that leave us with?

- anonymous

P1=P2

- JoannaBlackwelder

:-)

- anonymous

so what now ?

- JoannaBlackwelder

What do you think that means?

- anonymous

that the pressure same ?

- JoannaBlackwelder

Yep

- anonymous

so :
what would be the pressure of a given mass of a gas, if its volume and temperature are doubled same pressure ?

- JoannaBlackwelder

Yep, or "pressure is constant"

- anonymous

thanks a lot @JoannaBlackwelder :)

- JoannaBlackwelder

You're very welcome :-)

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