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anonymous
 one year ago
what would be the pressure of a given mass of a gas, if its volume and temperature are doubled ............. ?
anonymous
 one year ago
what would be the pressure of a given mass of a gas, if its volume and temperature are doubled ............. ?

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JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0P1V1/T1=P2V2/T2 when mass is constant.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0What happens when we sub in 2V1 for V2

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0And 2T1 for T2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0He wants to complement the question one word

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Ok, we are getting there.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer : mass is constant.?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0No, that is an assumption, since we aren't told how it will change.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Do you see how when the volume is doubled, that would be 2 times the original volume?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Ok, cool. And the same for temp?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so, can you plug those into the equation?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0That is the original equation. Can you plug in the other expressions we came up with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand sorry

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0It's cool. So, since V2 can be represented by 2V1, P1V1/T1=P2(2V1)/T2

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Does that step make sense?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0:) Can you try plugging in the expression for T2?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Not solve, substitute.

Melodious
 one year ago
Best ResponseYou've already chosen the best response.0that question i didnt understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0He wants to complement the question one word

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0P1V1/T1=P2(2V1)/(2T1) Do you see how I subbed that in?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Since T2 is 2T1

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0:) So, can you simplify?

Melodious
 one year ago
Best ResponseYou've already chosen the best response.0which grade chemistry ur talking about?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434392830978:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0I meant dw:1434392864965:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Thanks. :) The 2's canceldw:1434392913865:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Does that make sense?

Melodious
 one year ago
Best ResponseYou've already chosen the best response.0but which grade chemistry is this?????????

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0That's good, @Melodious but I was asking @soso707

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes @JoannaBlackwelder

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Great! So we are to dw:1434393062140:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Any ideas from here?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Please give it a shot. It is against policy to just give you the answers and we are mighty close to the answer.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0No, we just need to simplify what we have so far.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Using algebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434393687091:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Where did the equals sign go?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand what you mean.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0I still don't understand what you are trying to say. Can you show me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434394032412:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Hm, no, the equals sign can't just disappear.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0If we multiply both sides by T1, what happens? dw:1434394220901:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There will be less pressure?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0How do you get that?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0No, that's not what I get.dw:1434395143188:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434395174203:dw

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Is there anything else that can cancel?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Right, great!

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0So, what does that leave us with?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0What do you think that means?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that the pressure same ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so : what would be the pressure of a given mass of a gas, if its volume and temperature are doubled same pressure ?

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Yep, or "pressure is constant"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks a lot @JoannaBlackwelder :)

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0You're very welcome :)
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