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anonymous

  • one year ago

Help.. A 6-meter pole is supported by guy wires that are anchored to the ground as shown. What is sin D? A) 3/6.71 B) 6.71/6 C) 3/6 D) 6/6.71 Link to question is below πŸ‘‡πŸ‘‡

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  1. anonymous
    • one year ago
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    https://cdn.ple.platoweb.com/EdAssets/a750236adc844ccd805846bc0cb4d3e4?ts=635385786018600000

  2. mathstudent55
    • one year ago
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    Do you know SOHCAHTOA?

  3. anonymous
    • one year ago
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    Nope. πŸ˜ͺ

  4. mathstudent55
    • one year ago
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    SOHCAHTOA is a way to memorize which sides make the ratios of sine, cosine and tangent.

  5. anonymous
    • one year ago
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    okay katelyn what is the height

  6. anonymous
    • one year ago
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    basically katelyn what im saying sin=b/h

  7. anonymous
    • one year ago
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    Whaleee, the height of the triangles sides are both 6.71m I believe. The link I put has the picture of it if you need to refer to it. πŸ‘ŒπŸ˜„

  8. mathstudent55
    • one year ago
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    SOH: \(\sin \theta = \dfrac{opp}{hyp} \) CAH: \(\cos \theta = \dfrac{adj}{hyp} \) TOA: \(\tan \theta = \dfrac{opp}{adj} \) The initials S (sine), C (cosine), T (tangent), O (opposite leg), A (adjacent leg), and H (hypotenuse) are used in the mnemonic above.

  9. anonymous
    • one year ago
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    Mhm

  10. mathstudent55
    • one year ago
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    You are asked for the sine. Looking above, or remembering the SOH part of SOHCAHTOA, you see that \(\sin \theta = \dfrac{opp}{hyp} \)

  11. anonymous
    • one year ago
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    do you know what the answer is?

  12. anonymous
    • one year ago
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    Yes, opposite over hypotenuse

  13. mathstudent55
    • one year ago
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    Now look at angle D. For angle D, which side is the opposite leg? Which side is the hypotenuse?

  14. anonymous
    • one year ago
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    no..

  15. anonymous
    • one year ago
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    do you know what the base if a triangle is?

  16. mathstudent55
    • one year ago
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    |dw:1434392815161:dw|

  17. mathstudent55
    • one year ago
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    |dw:1434392858828:dw|

  18. anonymous
    • one year ago
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    Oh crap @mathstudent55 I totally forgot...oh.....ok so I get you

  19. mathstudent55
    • one year ago
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    Fill in the blanks: |dw:1434392884772:dw|

  20. anonymous
    • one year ago
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    And @bdavis07 uhhh, the base? i think since one side is 3 the other must be 3 so its 6 and @mathstudent55 ok, hold up let me think.....ok 6/6.71 would be sin

  21. anonymous
    • one year ago
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    no no no. base is three and the height is 6 so b/h

  22. anonymous
    • one year ago
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    base over height

  23. mathstudent55
    • one year ago
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    The 3 m base of the small triangle to the left, or the 6 m base of the entire triangle, is not used in this problem. All we need here is the opposite leg and the hypotenuse since the sine ratio is the ratio of the opposite leg to the hypotenuse.

  24. anonymous
    • one year ago
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    OKKKKK oh my goodness thank you so much!!! Honestly, I didn't even read it....I was just trying to get the answer fast....maybe I'm to honest...aha...lol thanks. I'm in summer school so this stuff is pretty overwhelming because i've forgotten a lot and i'm not that good at geometry..Thankyou both very much. πŸ˜„

  25. mathstudent55
    • one year ago
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    |dw:1434393143216:dw|

  26. anonymous
    • one year ago
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    6.71 and 3

  27. mathstudent55
    • one year ago
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    Don't get overwhelmed. Just study a lot, and ask lots of questions. That's how you learn.

  28. anonymous
    • one year ago
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    your welcome katelyn

  29. anonymous
    • one year ago
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    Thanks for the advice πŸ˜„πŸ‘Œ

  30. mathstudent55
    • one year ago
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    |dw:1434393288530:dw|

  31. mathstudent55
    • one year ago
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    The answer is \(\sin D = \dfrac{6}{6.71} \)

  32. mathstudent55
    • one year ago
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    @bdavis07 There is no base/height here.

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