anonymous
  • anonymous
Fan and Medal!... A lottery is set up in which players pick six numbers from the set 1, 2, 3, ... , 39, 40. How many different ways are there to play this lottery? (In this game the order in which the numbers are picked does NOT matter.)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@kropot72
kropot72
  • kropot72
This problem asks for the number of combinations of 40 numbers taken 6 at a time. There are 40 choices for the first number, having chosen the first number there are 39 choices for the second number, 38 choices for the third number, and so on giving \[40\times39\times38\times37\times36\times35=(you\ can\ calculate)\ ways\]
anonymous
  • anonymous
276,363,3600?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

kropot72
  • kropot72
However the question states that order of selection does not matter, therefore the result of the above calculation must be divided by \[\large 6\times5\times4\times3\times2\times1\] this being the number of permutations of each selection.
anonymous
  • anonymous
720
kropot72
  • kropot72
So we have \[\large \frac{2,763,633,600}{6\times5\times4\times3\times2\times1}\]
kropot72
  • kropot72
Yes, the denominator is 720.
anonymous
  • anonymous
thank you so much @kropot72 sorry for the late responses im on babysitting duty
kropot72
  • kropot72
You're welcome :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.