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Loser66
 one year ago
Starting with 2 sets A and B of respective cardinalities a and b, use all operations on sets that you have learnt:
1) to construct sets whose cardinalities are the following
2) to construct wordproblems whose solutions require counting the numbers of the sets you first constructed
a) (b+a)(ba)
b) b^{a+b}
Please, help.
Loser66
 one year ago
Starting with 2 sets A and B of respective cardinalities a and b, use all operations on sets that you have learnt: 1) to construct sets whose cardinalities are the following 2) to construct wordproblems whose solutions require counting the numbers of the sets you first constructed a) (b+a)(ba) b) b^{a+b} Please, help.

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Loser66
 one year ago
Best ResponseYou've already chosen the best response.0I don't know how to start.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@loser66 Can we start with a list of the operations you've learned?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Whatever you use, I am ok.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0sorry @Loser66 i haven't a clue about this kind of stuff :(

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0If you're vague about this, then I assume you know at least union, intersection, difference, and complement, right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0It's ok, friend, neither I.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to find A\(\cap\)B in terms of A and B, using the above operators?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0yes, I do. But first off, I need you to define what are set A and B, please

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Since the problem has 2 parts, operation and word problem. We can go backward by defining the sets first and then work on it, right?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0The same as in your question, i.e. with cardinalities a and b. But we don't use them for now. Is that ok?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Actually, I was planning to use a+b = A+B=A\(\cap\)B+A\(\cup\)B, and similarly ab, but then it's not a set, which is what the question asks. Perhaps @ganeshie8 has a better idea.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0I have to go for work now. I will be back after work. If you have any idea, please guide me. I will take it later. Much appreciate.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Are the sets disjoint?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Hold on, I'll post a pic of my work.

freckles
 one year ago
Best ResponseYou've already chosen the best response.0@Kainui or @mukushla Question about sets maybe you might be able to help with.
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