!!

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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reaplce a with -1 and b with 2 or vice versa that is you can do either: \[\frac{f(2)-f(-1)}{2-(-1)} \text{ or } \frac{f(-1)-f(2)}{-1-2}\]
now if you want to continue you would need to know the meaning of f(x) like the graph or the expression it is assigned to
impossibly for me to know if that is right or wrong since you still haven't said what f was

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ok so f(2)=? look on the x-axis and find x=2 there the find the y value that corresponds to x=2
where is the line at when x=2?
So, X=2 and Y=0?
yes so f(2)=0
now we need to find f(-1)
where is the line at when x=-1?
Is that Y=4?
yep so f(-1)=4
now we plug in
\[\frac{f(2)-f(-1)}{2-(-1)}=\frac{0-4}{2-(-1)}\]
0-4=? 2-(-1)=?
-4/3 ?
yep sounds awesome and it doesn't matter if you did the other way: \[\frac{f(-1)-f(2)}{-1-2}=\frac{4-0}{-1-2}=\frac{4}{-3}=-\frac{4}{3}\] you still get -4/3
Awesome! Thanks so much for the help!
np

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