Which polynomial identity will prove that 65 = 81 - 16? Binomial Multiplication Difference of Cubes Sum of Cubes Difference of Squares

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Which polynomial identity will prove that 65 = 81 - 16? Binomial Multiplication Difference of Cubes Sum of Cubes Difference of Squares

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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B
Why?
81 = 9^2 hint2 : 16 = 4^2 65 = 81-16 = 8^2 - 4^2 = (9+4)(9-4) = (13)(6) = 65

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It's not B. What do you think the answer should be and why? Try to reason, logically.
I have no idea because none of those numbers are squared or cubed but theyre being subtracted so I would go with the difference of. So B or D
Yes, the answer is D. This is because 81 and 16 are perfect squares. That means, \(9^2 = 81\) \(4^2 = 16\) \(65 = 81 - 16 = 9^2 - 4^2 = difference ~~of~~ perfect ~~squares = D\)

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