anonymous
  • anonymous
A baseball is hit almost straight up into the air with a speed of 22m/s. Estimate how high it goes and how ling it is in the air
Physics
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anonymous
  • anonymous
A baseball is hit almost straight up into the air with a speed of 22m/s. Estimate how high it goes and how ling it is in the air
Physics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
looks like "almost straight up" should be considered as 90ยบ angle for the initial velocity, i.e. only y-component, in such case the velocity for the ball at any time is: \[v(t)=v_0-gt\] in this case \(v_0=22m/s\) the height of the ball at anytime is given by: \[y(t)=y_0+v_0t-\frac{1}{2}gt^2\] to determine the time it takes to get to the highest point \(H\) we can set the speed to 0, since at that point the ball stops for an instant: \[v_0-gt=0\] with the time we get from that eq. we can calculate \(H\) using the equation for \(y(t)\) give it a try!

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