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anonymous
 one year ago
I NEED HELP ASAP PLEASE AND THANK YOU!
The diameter of the base of a right cone is 8 cm. If the total surface area of the cone is 164(pi) cm2, what is the length of the slant height? (Will Medal and Fan for best answer)
anonymous
 one year ago
I NEED HELP ASAP PLEASE AND THANK YOU! The diameter of the base of a right cone is 8 cm. If the total surface area of the cone is 164(pi) cm2, what is the length of the slant height? (Will Medal and Fan for best answer)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Ashleyisakitty If you could help me i would very mich appreciate it! :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha could you help me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[A=\pi r (r+\sqrt{h^2+r^2})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is the formula for the surface area

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hold on this is a multiple choice question so these are the answers i just need to narrow it down 12.5 cm 19.5 cm 37 cm 45 cm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434408597776:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay the formula will help me hold on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i kept getting 9.05 for the slant height

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we need to find the height using the formula and then use pythagorean to find the slant length

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah but it isnt one of the answers. You have to square root 17 so i was wondering if i should just put 17

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i didn't see that pi, let me try again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ill go with that thank you very much
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