## Here_to_Help15 one year ago Assistance is needed thanks :)

1. Here_to_Help15

2. anonymous

you can use the relation between $$sin(\beta)$$, the hypothenuse $$BC$$ and the side $$AC$$: $\sin(\beta)=\frac{AC}{BC}$

3. Here_to_Help15

Example ?

4. Here_to_Help15

@Greg_D ?

5. anonymous

the angle $$\beta=45º$$ in this problem, and $$AC=17ft$$, you can use those values and find $$BC$$, it is pretty straightforward...

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