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Here_to_Help15
 one year ago
Assistance is needed thanks :)
Here_to_Help15
 one year ago
Assistance is needed thanks :)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can use the relation between \(sin(\beta)\), the hypothenuse \(BC\) and the side \(AC\): \[\sin(\beta)=\frac{AC}{BC}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the angle \(\beta=45º\) in this problem, and \(AC=17ft\), you can use those values and find \(BC\), it is pretty straightforward...
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