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anonymous

  • one year ago

Rewrite in simplest radical form X^5/6 over x^1/6 Show each step of your process.

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  1. anonymous
    • one year ago
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    @lizz123

  2. lizz123
    • one year ago
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    @Ashleyisakitty

  3. lizz123
    • one year ago
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    @jim_thompson5910

  4. anonymous
    • one year ago
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    @KEYS

  5. jim_thompson5910
    • one year ago
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    |dw:1434411658371:dw|

  6. jim_thompson5910
    • one year ago
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    |dw:1434411694412:dw|

  7. jim_thompson5910
    • one year ago
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    since the bases are the same (both x), we can subtract the exponents (top - bottom) |dw:1434411735859:dw|

  8. jim_thompson5910
    • one year ago
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    |dw:1434411774461:dw|

  9. jim_thompson5910
    • one year ago
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    I'll let you finish up

  10. anonymous
    • one year ago
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    x^4/6

  11. anonymous
    • one year ago
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    yes? @jim_thompson5910

  12. jim_thompson5910
    • one year ago
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    you can then reduce 4/6 to get what?

  13. anonymous
    • one year ago
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    2/3

  14. jim_thompson5910
    • one year ago
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    correct |dw:1434412037037:dw|

  15. anonymous
    • one year ago
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    But we aren't done right?

  16. jim_thompson5910
    • one year ago
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    that's the final answer

  17. jim_thompson5910
    • one year ago
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    we can't reduce 2/3 any further

  18. anonymous
    • one year ago
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    |dw:1434412118662:dw|

  19. jim_thompson5910
    • one year ago
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    ah they want you to convert to radical form

  20. jim_thompson5910
    • one year ago
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    Rule: \[\LARGE x^{m/n} = \sqrt[n]{x^m}\]

  21. jim_thompson5910
    • one year ago
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    m = 2 n = 3 \[\LARGE x^{m/n} = \sqrt[n]{x^m}\] \[\LARGE x^{2/3} = \sqrt[3]{x^2}\]

  22. anonymous
    • one year ago
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    Okay:) Thank-you. Mind if I ask another?

  23. jim_thompson5910
    • one year ago
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    sure go ahead

  24. anonymous
    • one year ago
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    Is the expression x3•x3•x3 equivalent to x3•3•3? Why or why not? Explain your reasoning.

  25. jim_thompson5910
    • one year ago
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    what are your thoughts on it

  26. anonymous
    • one year ago
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    |dw:1434412295575:dw|

  27. anonymous
    • one year ago
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    That was the first equation, if u can read it

  28. anonymous
    • one year ago
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    |dw:1434412377772:dw|

  29. anonymous
    • one year ago
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    That's the 2nd one.

  30. jim_thompson5910
    • one year ago
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    what are your thoughts on this? were you able to get started at all?

  31. anonymous
    • one year ago
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    Ok so I don't think they are equal

  32. jim_thompson5910
    • one year ago
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    and why is that?

  33. anonymous
    • one year ago
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    because one is x^27

  34. anonymous
    • one year ago
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    and I don't know about the other.

  35. jim_thompson5910
    • one year ago
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    |dw:1434412588940:dw|

  36. jim_thompson5910
    • one year ago
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    the first one, you use the rule \[\Large x^a*x^b = x^{a+b}\]

  37. jim_thompson5910
    • one year ago
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    and you can extend out the rule the rule basically says "if the bases are the same, then you add the exponents" |dw:1434412649041:dw|

  38. jim_thompson5910
    • one year ago
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    |dw:1434412662937:dw|

  39. jim_thompson5910
    • one year ago
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    Or you can replace x with some small number, say x = 2 then compute x^3*x^3*x^3 and x^(3*3*3) to see if they are equal or not

  40. anonymous
    • one year ago
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    x^9 for the second equation right?

  41. jim_thompson5910
    • one year ago
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    |dw:1434412780279:dw|

  42. anonymous
    • one year ago
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    So they aren't equal? Right?

  43. jim_thompson5910
    • one year ago
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    yeah first one is x^9 the second is x^27

  44. jim_thompson5910
    • one year ago
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    I would also use numbers in place of x to test too

  45. anonymous
    • one year ago
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    Ok! That's a good idea!! :)

  46. anonymous
    • one year ago
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    I have two more questions, and I'm done. Please?

  47. jim_thompson5910
    • one year ago
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    I'll help with one more

  48. anonymous
    • one year ago
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    Thank you:)

  49. anonymous
    • one year ago
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    Which of the following expressions are equivalent? Justify your reasoning. A. 4√x3 B. 1/ x−1 C. 10√x^5•x^4•x^2 D. x^1/3 times x^1/3 times x^1/3

  50. anonymous
    • one year ago
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    @jim_thompson5910

  51. jim_thompson5910
    • one year ago
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    can you draw out answer C? it's hard to tell where the root ends

  52. anonymous
    • one year ago
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    It's over the whole thing, except the 10

  53. jim_thompson5910
    • one year ago
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    so it is \[\Large 10\sqrt{x^5*x^4*x^3}\] ???

  54. anonymous
    • one year ago
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    Yes

  55. jim_thompson5910
    • one year ago
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    what does \[\Large x^5*x^4*x^3\] simplify to?

  56. anonymous
    • one year ago
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    x^11

  57. jim_thompson5910
    • one year ago
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    close

  58. jim_thompson5910
    • one year ago
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    oh wait I have the wrong digit

  59. jim_thompson5910
    • one year ago
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    it should be \[\Large 10\sqrt{x^5*x^4*x^2}\]

  60. jim_thompson5910
    • one year ago
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    so yeah, 11

  61. jim_thompson5910
    • one year ago
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    ok I see the answer now

  62. jim_thompson5910
    • one year ago
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    what does x^1/3 times x^1/3 times x^1/3 simplify to?

  63. anonymous
    • one year ago
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    x^3/3

  64. jim_thompson5910
    • one year ago
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    the 3/3 turns into 1/1 or just 1 x^1 = x

  65. jim_thompson5910
    • one year ago
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    so in the end, x^1/3 times x^1/3 times x^1/3 turns into just x

  66. jim_thompson5910
    • one year ago
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    does choice B say this \[\Large \frac{1}{x^{-1}}\] ??

  67. anonymous
    • one year ago
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    yes

  68. jim_thompson5910
    • one year ago
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    so, \[\Large \frac{1}{x^{-1}} = \frac{1}{1/x} = \frac{x}{1} = x\]

  69. anonymous
    • one year ago
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    Ok

  70. anonymous
    • one year ago
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    so, b and d basically

  71. jim_thompson5910
    • one year ago
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    yes

  72. anonymous
    • one year ago
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    Thank-you so much for all your help:)

  73. jim_thompson5910
    • one year ago
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    yw

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