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anonymous
 one year ago
Thanks for helping! This question is really weird :(
r=6sin theta
I need to multiply both sides of the equation by r and use r^2=x^2+y^2 to rewrite the equation in terms of x and y.
anonymous
 one year ago
Thanks for helping! This question is really weird :( r=6sin theta I need to multiply both sides of the equation by r and use r^2=x^2+y^2 to rewrite the equation in terms of x and y.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Ashleyisakitty @jim_thompson5910 @zepdrix @Nnesha @e.mccormick @wio @sammixboo @kropot72 @mathmate

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Ok so you want to convert it to rectangular, it's good you notice we have to multiply r and use \[r^2 = x^2+y^2\] we know the ratio for sin theta is the following \[\sin \theta = \frac{ y }{ r }\] so we have \[r =  6\left( \frac{ y }{ r } \right)\] can you finish it off?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure I understand where to go from there

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Why? Look at what we know, and we want to "get rid" of the polar coordinates.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I don't know what that means

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Hint: \[r^2 = x^2+y^2\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Yes, that looks good :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You can rearrange it and what not if you wish

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is it in terms of x and y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm asked to complete the square to produce another equation in my worksheet. Should I do it from this form?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You may complete the square

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Ah, yes we have to complete the square, you know how to do that right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2When you have it as such \[6y=x^2+y^2 \] it's always best to complete the square as it will be in terms of x and y.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know how to do it in regular form, but I'm sort of confused about this one

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[6y = x^2+y^2 \implies x^2+y^2 + 6y = 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I thought it was when you added (b/2)^2 to both sides or something like that

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I didn't complete the square...I put in a form so you can complete the square.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2So we don't need to worry about the x^2, now complete the square for y^2+6y

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2When you have \[x^2+ax \implies x^2+ 2 \frac{ ax }{ 2 } + \left( \frac{ a }{ 2 } \right)^2\left( \frac{ a }{ 2 } \right)^2\] to complete the square.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't that make it remain the same?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, I suck at pre calc :(

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You should try it, otherwise me doing everything is not going to help you :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But when plugging in y^2+6y in, it cancels back to y^2+6y, no?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Mhm, no you don't do that, we don't plug in anything I just put if you have the form y^2+6y you do the following > .....etc

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[x^2+ax \implies x^2+ 2 \frac{ ax }{ 2 } + \left( \frac{ a }{ 2 } \right)^2\left( \frac{ a }{ 2 } \right)^2\] \[x^2+ ax \implies y^2+6y\] in your question

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434416994934:dw now we just factor

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434417167196:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2So now we have \[x^2+y^2+6y+9 = 9\] one step away from completing it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You were right, but you put 6x instead of 6y :P

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2That should be = 9 not 9, yes you want it to look as such \[\huge x^2+(y+3)^2 = 9 \] that's your final answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh whoop, same thing ha ha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the help!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2No problem, it makes sense now? :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Awesome, glad to hear it, make sure you go over it again!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Of course :), have a good day
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