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anonymous

  • one year ago

having a mental skid... how do you calculate by hand the derivative for Log [1/x] ?

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  1. anonymous
    • one year ago
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    I know Log[x] --> 1/x but it cant be 1/(1x) can it?

  2. jim_thompson5910
    • one year ago
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    if the log is base e, ie a natural log, then log(1/x) = log(x^(-1)) = -1*log(x) then you would derive that to get -1/x

  3. anonymous
    • one year ago
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    yes thats the base .. ahh right on.. extract the -1 via the exponent.

  4. anonymous
    • one year ago
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    does it help to know that \[\log(\frac{1}{x})=-\log(x)\]

  5. anonymous
    • one year ago
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    yes they both help.. thanks... whats the name of that identity there satellite?

  6. dan815
    • one year ago
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    log power rule, log (x^a) = a*log(x)

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