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anonymous

  • one year ago

I need help!!!

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  1. anonymous
    • one year ago
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    @xapproachesinfinity

  2. Ehsan18
    • one year ago
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    about what?

  3. anonymous
    • one year ago
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    How to do it.

  4. xapproachesinfinity
    • one year ago
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    question?

  5. Kash_TheSmartGuy
    • one year ago
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    Where is the question?

  6. anonymous
    • one year ago
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    I need help figuring out how to answer the question

  7. anonymous
    • one year ago
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    Did any of you get the picture?

  8. xapproachesinfinity
    • one year ago
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    you mean the previous one \[\frac{\sqrt{9}}{\sqrt[6]{9}}\] what you need too use is the properrty \(\sqrt[n]{a}=a^{\frac{1}{n}}\)

  9. anonymous
    • one year ago
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    No not the previous question

  10. anonymous
    • one year ago
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    This question

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  11. xapproachesinfinity
    • one year ago
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    then after that use the property \(\frac{a^n}{a^m}=a^{n-m}\)

  12. xapproachesinfinity
    • one year ago
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    oh ok

  13. anonymous
    • one year ago
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    @Ehsan18

  14. anonymous
    • one year ago
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    I don't know how to use that property

  15. xapproachesinfinity
    • one year ago
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    well it is really the same stuff

  16. xapproachesinfinity
    • one year ago
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    well if you have \[\sqrt{9}=9^{1/2}\] that's how you turn radical to power

  17. anonymous
    • one year ago
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    Ok so how do I get the whole question?

  18. xapproachesinfinity
    • one year ago
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    \[\sqrt[4]{9}=9^{1/4}\]

  19. xapproachesinfinity
    • one year ago
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    well don't you know how to do \[a^n\times a^m=a^{n+m}\] use this for the top

  20. anonymous
    • one year ago
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    Isn't this an exam Q? @Nicole2525

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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