anonymous
  • anonymous
I need help!!!
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@xapproachesinfinity
Ehsan18
  • Ehsan18
about what?
anonymous
  • anonymous
How to do it.

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xapproachesinfinity
  • xapproachesinfinity
question?
Kash_TheSmartGuy
  • Kash_TheSmartGuy
Where is the question?
anonymous
  • anonymous
I need help figuring out how to answer the question
anonymous
  • anonymous
Did any of you get the picture?
xapproachesinfinity
  • xapproachesinfinity
you mean the previous one \[\frac{\sqrt{9}}{\sqrt[6]{9}}\] what you need too use is the properrty \(\sqrt[n]{a}=a^{\frac{1}{n}}\)
anonymous
  • anonymous
No not the previous question
anonymous
  • anonymous
This question
1 Attachment
xapproachesinfinity
  • xapproachesinfinity
then after that use the property \(\frac{a^n}{a^m}=a^{n-m}\)
xapproachesinfinity
  • xapproachesinfinity
oh ok
anonymous
  • anonymous
@Ehsan18
anonymous
  • anonymous
I don't know how to use that property
xapproachesinfinity
  • xapproachesinfinity
well it is really the same stuff
xapproachesinfinity
  • xapproachesinfinity
well if you have \[\sqrt{9}=9^{1/2}\] that's how you turn radical to power
anonymous
  • anonymous
Ok so how do I get the whole question?
xapproachesinfinity
  • xapproachesinfinity
\[\sqrt[4]{9}=9^{1/4}\]
xapproachesinfinity
  • xapproachesinfinity
well don't you know how to do \[a^n\times a^m=a^{n+m}\] use this for the top
anonymous
  • anonymous
Isn't this an exam Q? @Nicole2525

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