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anonymous
 one year ago
Extremely quick question! Thank You!
Is w=22i in polar form 2sqrt(2)(cos(pi/4)+isin(pi/4))?
anonymous
 one year ago
Extremely quick question! Thank You! Is w=22i in polar form 2sqrt(2)(cos(pi/4)+isin(pi/4))?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Ashleyisakitty @satellite73 @jim_thompson5910 @campbell_st @zepdrix @TheSmartOne @Nnesha @Luigi0210 @Compassionate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm worried theta might be wrong

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3hmm ya, it can't be pi/4 right? we're in quadrant `three` if both the real and imaginary part are negative.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02/2=1 So I thought that was why. Is there a rule I don't know?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3Well, when you apply your arctangent (im assuming that's what you're doing),\[\Large\rm \arctan\left(\frac{2}{2}\right)=\theta\]Yes, you end up with pi/4 as a reference angle. But this really corresponds to two angles in one full rotation. You have to look back at your rectangular form to see where you should be.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3Since they're both negative, we need the NEXT angle, which will be pi/4 + pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I see what you mean.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not to butt in, but drawing a picture is real helpful by which i only mean "plot the point"

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.3ya 5pi/4 sounds better :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, gotcha @satellite73

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it will keep you from doing something silly like taking \[\tan^{1}(\frac{b}{a})\] which does not really work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 yup, I'll do that next time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the help everyone :D
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