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anonymous

  • one year ago

what is the probability of spinning doubles with a spinner of 3 and a spinner of 6 numbered 1-3 and 1-6?

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  1. anonymous
    • one year ago
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    |dw:1434422377136:dw|

  2. xapproachesinfinity
    • one year ago
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    a spiner has 0 to 9?

  3. xapproachesinfinity
    • one year ago
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    oh ok

  4. anonymous
    • one year ago
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    I don't know if i typed the question to make sense

  5. xapproachesinfinity
    • one year ago
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    is the question as it is written or you change it?

  6. xapproachesinfinity
    • one year ago
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    well let's P((1,3) and (1,6) this the desired prob

  7. xapproachesinfinity
    • one year ago
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    P((1,3) and (1,6))=P((1,3))P((1,6))

  8. anonymous
    • one year ago
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    So it gives me the spinners i drew and it gives me a Chart |dw:1434422759820:dw|

  9. xapproachesinfinity
    • one year ago
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    now we find p((1,3)) we need to all the possible pairs here

  10. xapproachesinfinity
    • one year ago
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    hmm how is that helpful?

  11. anonymous
    • one year ago
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    and it just asks what is the probability of spinning double threes

  12. xapproachesinfinity
    • one year ago
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    i would do it this way (1,1)(1,2)(1,3)(1,4)(1,5)(1,6) (2,1)(2,2)(2,3)(2,4)(2,5)(2,6) (3,1)(3,2) (3,3)(3,4)(3,5)(3,6) and go on out of this how many are (1,3) i think (3,1) is different

  13. xapproachesinfinity
    • one year ago
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    same go with (1,6)

  14. xapproachesinfinity
    • one year ago
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    or does it matter from which spinner gives 1 or 3?

  15. xapproachesinfinity
    • one year ago
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    if that matter we need to narrow that list down

  16. anonymous
    • one year ago
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    Nope it doesn't matter. Thank you! Ill do that!

  17. xapproachesinfinity
    • one year ago
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    just to clear one misundertanding i said P(1.3 and 1,6) that is not the case they are asking for two probabs p(1,3) p(1,6) two distinct questions

  18. xapproachesinfinity
    • one year ago
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    well i think it is clear now :)

  19. kropot72
    • one year ago
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    The probability of spinning a 1 on the spinner of 3 is 1/3. The probability of spinning a 1 on the spinner of 6 is 1/6. Therefore the probability of a double 1 is given by \[\large \frac{1}{3} \times \frac{1}{6}\]. The probability of a double 2 will be the same as for a double 1, and the probability of a double 3 will also be the same as the probability of a double 1. The events 'double 1', 'double 2' and 'double 3' are mutually exclusive, therefore the probability of spinning doubles is given by \[\large P(doubles)=3\times\frac{1}{3}\times\frac{1}{6}\]

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