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anonymous
 one year ago
(x+2)(x3)=(x3)^2
anonymous
 one year ago
(x+2)(x3)=(x3)^2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is the short answer for this equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solving for X I got 3/11 or .27 in fraction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do u deal with it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well (x+2)(x3) would be xx6 and (x3)^2 would be x^26x+9. So xx6 = x^26x+9

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0part of the FOIL process is wrong.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0for (x+2)(x3) we have (x)(x)+(x)(3)+2(x)+(2)(3) which is x^23x+2x6=x^2x6

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0similarly, (x3)^2 means write (x3) twice based on the exponent number, so we have (x3)(x3) = x^23x3x+9 = x^26x+9

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(x+2)(x3) = (x3)^2\] \[(x+2)(x3) = x ^{2}x 6\] \[(x3)^{2}= x ^{2}6x +9\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0^ yes exactly.. \[x^2x6=x^26x+9\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0is this a solve for x problem? like if I shift everything to the right we will have \[x^2x6x^2+6x9=0\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0since the x^2 cancels out can you tell me what x+6x and 69 is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll Did you mean x +6x = 6x + 9

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0but I'm shifting everything to the left... all signs from the right change.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[(x+2)(x3) = (x3)^2 \] \[x^2x6=x^26x+9\] \[x^2x6x^2+6x9=0 \] the question op is asking is vague... so I'm not sure if this is a solve for x problem or something else

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It will be simpler to solve by keeping the x on the left and the numbers on the right

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0if you are solving for \(x\) \[(x+2)(x3)=(x3)^2\] \[(x+2)(x3)(x3)^2=0\] \[[(x+2)(x3)](x3)=0\] \[[x+2x+3](x3)=0\] \[5(x3)=0\] so \(x=3\)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yeah I was going to do that... since the x^2's cancel out I have \[5x15 = 0 \rightarrow 5(x3)=0\]

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0or you do the following \[(x+2)(x3)=(x3)^2\] clearly x=3 is a solution...then cancel \[x+2=x3\] cancel out the x's so 2=3 which is not possible...so x=3 is the only solution

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0but again what is OP asking in here besides that question? It's just an equation. That can be anything out there.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0@LeibyStrauss I rather shift everything to the left and combine like terms... it's how I've done it when I learned the material. I don't want alternatives... it only creates drama between me and the person . just like in real life with the quadratic equation and my professor factored something out thinking that it will look simpler which was actually real hard.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0It didn't look simpler...it looked worse.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0wow @Zarkon that technique is actually much faster :O because if I let x= 3 we have 33 on the left and right forcing the equation to look like 0=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll You taught me a new way how to solve it

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0well...one of my professors always said that you can solve any math problem with different methods as long as it doesn't break the math rules.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. I solved it as follows: x 6 = 6x + 9 Add 6x and 6 to both sides 5x = 15 divide both sides by 5 x = 15/5 We both got the same answer, but solving differently.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let's solve your equation stepbystep. (x+2)(x−3)=(x−3)2 Step 1: Simplify both sides of the equation. x2−x−6=x2−6x+9 Step 2: Subtract x^2 from both sides. x2−x−6−x2=x2−6x+9−x2 −x−6=−6x+9 Step 3: Add 6x to both sides. −x−6+6x=−6x+9+6x 5x−6=9 Step 4: Add 6 to both sides. 5x−6+6=9+6 5x=15 Step 5: Divide both sides by 5. 5x5=155 x=3 Answer: x=3
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