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anonymous
 one year ago
Which of these shows the graph for the quadratic function
y = x^2 + 2x + 3?
anonymous
 one year ago
Which of these shows the graph for the quadratic function y = x^2 + 2x + 3?

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3ok first of all do not spam and mass tag. I wouldn't want you to end up getting a warning or suspended as this is against OpenStudy's Code of Conduct and Terms of Service.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey your picture is rolanda!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3Everyone, I got this question under control, so anyway... we need to create a chart that looks like x y = x^2+2x+3 then we just select any x... and solve for that y.... once we have done that, we can pick more x's that will give more y = results and we will have more coordinate points.. For example, if my x = 0 Then x y = x^2+2x+3 0 y=0^2+2(0) +3 0 y =3 so or first coordinate point is (0,3). You graph that on your scratch paper... then you let x be any positive or negative number and continue until your graph matches one of the choices you are given.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no please stay i really need help

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3but there are mods in here and I'm not going to give direct answers... my task as a tutor is to teach and guide, not spoonfeed.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they are here to help too

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I already gave you an example on how to solve for this ... please try to understand and attempt the work... then you can answer here and I'll check to see if you're on the right track or not.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand @UsukiDoll explanation is it possible for someone else to explain it like @ganeshie8 @Michele_Laino

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3@ganeshie8 @Michele_Laino... did I not just give an example and explain this thoroughly?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u did but im just not understanding it

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0I think you gave a good explanation @UsukiDoll :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3see....I'm being thrown under the bus here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not throwing u under the bus... i have a disease where i need everything to be explained extra cause i cant remember concepts and my brain is messed up cause it hurts to think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a birth defect... :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its called Cerebellar Ataxia

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0another way is: the xccordinate of the vertex of a parabola like this: \[y = a{x^2} + bx + c\] is: \[x =  \frac{b}{{2a}}\] now, by comparison with your parabola, what are the coefficient a, b, and c, and what is the xcoordinate of the vertex of your parabola?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3there is more than one way to solve this...maybe that method is too complex for OP?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3alright.. I'll try again... what she gave was from College Algebra and seeing as you're not at level yet, we'll go back to what I've just put earlier.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3we are given \[y = x^2 + 2x + 3\] and the question asks which graph is the same as the quadratic equation

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, please ignore my hint @barbdewysveck1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3what we can do....is to create a table a table like x y =x^2+2x+3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3so, we can pick any x and plug it in the y=x^2+2x+3

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3For example, if I pick x = 0. I replace all x's in the y equation x y=x^2+2x+3 0 y=(0)^2+2(0)+3 0^2, also means 0 written twice (0)(0) = 0 2(0) means 2 x 0 which is also 0 so now we have 0 0+0+3 (we add this together and that's 3) so you're first coordinate point is (0,3)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3well... we only have one point... we need more than (0,3) for a clearer picture

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3so we continue by picking another x... how about if x = 1 so I plug x = 1 into y=x^2+2x+3 1 y=(1)^2+2(1)+3 (1)^2 means (1)(1) = 1 x 1 = 1 2(1) means 2 x 1 and that's 2 so we add up 1+2+3 and we have y = 6 so our next point is (1,6)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434428975864:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I connect those two points after I graph them dw:1434429072437:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay can u help me with more

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3because we started at (0,3) and by plotting (1,6) we noticed that the graph was really high up... so only 1 graph was the same as our drawing

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3ok... all we need to is to draw out y=x^2+2x3 using the same techniques we did and from there we can find the vertex. The vertex of a parabola is the point where the parabola crosses its axis of symmetry.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3we can just pick our x to be 1,0, and 1 x y=x^2+2x3 0 y=0^2+2(0)3 as before 0^2 means writing 0 twice (two times ) but 0 x 0 = 0 similarly 2(0) means 2 x 0 which is again 0 so we have 0+03 which is 3 our first point is (0,3)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434429432668:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3it's not drawn to scale... so the graph is a bit ugly...it's just a rough sketch

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer is B!!!!!!!!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3umm not yet.. for many reasons 1. we don't have enough information 2. we aren't sure if the graph is really above or below the xaxis

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3we are also not sure if it's on the xaxis or yaxis.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my teacher said to look at this

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3x y=x^2+2x3 so if x = 1 y = (1)^2+2(1)3 = 1+23=33=0 so the next point is (1,0) if x = 1 y=(1)^2+2(1)3 = 123 =13=4 (1,6)dw:1434429719251:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since the example she gave me is +3 and mine is 3 im just gonna go with the opposite of the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so im gonna go with b

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I don't think that's a great idea. . . in fact.... that's not a good strategy

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3there is more than one method to solve these problems as long as it doesn't break any math rules... we are using the graphing method to find the vertex which is the lowest or highest point of the graph. In this case, it's the lowest point of the graph which is caused by (1,4)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434430022195:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I need another point to complete this parabola... if I have x = 3 I should have y = 0 I have y = 0 in the right, now I need y =0 in the left y=x^2+2x3 = (3)^2+2(3)3 = 963 =33=0 dw:1434430081244:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434430156778:dw yes ... do you know why?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3ok, can you explain to me why the answer is below the x axis ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok this next one i already answered i just need u to say if im right or not, k?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3alright but can you please answer my question first? I want to see if you understand why it's below the xaxis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because the vertex of the parabola is the point where the parabola crossed its axis of symmetry and that happened under the xaxis. BOOM!!!!!!!!!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3yes and also (1,4) is the lowest point in the graph... and since the vertex is (1,4) it is indeed under the xaxis.. ok we can move on to the next question .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think the answer is 1

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3ok this time we have to use the discriminant which is b^24ac our equation y=4x^2+3x+2 is in the form of y=ax^2+bx+c. So we let a = 4, b =3, and c = 2 plugging these values into the discriminant gives us (3)^24(4)(2) 94(8) = 9+32=41 I got a massive number.. I'm reading that if the discriminant is 0, there is 1 solution discriminant is negative > no solution discriminant is positive > 2 solutions

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I need the quadratic equation to go further.. hold on \[\LARGE \begin{array}{*{20}c} {x = \frac{{  3 \pm \sqrt {41} }}{{8}}} \\ \end{array}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3\[\LARGE \begin{array}{*{20}c} {x = \frac{{  3 + \sqrt {41} }}{{8}}} \\ \end{array}\] \[\LARGE \begin{array}{*{20}c} {x = \frac{{  3  \sqrt {41} }}{{8}}} \\ \end{array}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3the negatives cancel out for the second one \[\LARGE \begin{array}{*{20}c} {x = \frac{{ 3 + \sqrt {41} }}{{8}}} \\ \end{array}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3\[\LARGE \begin{array}{*{20}c} {x = \frac{{  3 + \sqrt {41} }}{{8}}} \\ \end{array}\] \[\LARGE x = \frac{3}{8}\frac{\sqrt{41}}{8}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3the discriminant was positive to begin with... and I don't see any negative signs inside the radical, so we have 2 solutions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u check this one too?
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