anonymous
  • anonymous
Which of the following is an even function? g(x) = (x – 1)2 + 1 g(x) = 2x2 + 1 g(x) = 4x + 2 g(x) = 2x
Mathematics
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anonymous
  • anonymous
Which of the following is an even function? g(x) = (x – 1)2 + 1 g(x) = 2x2 + 1 g(x) = 4x + 2 g(x) = 2x
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
sorry i don't rember :/

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anonymous
  • anonymous
f(-a)=f(a) then f(x) is an even function
anonymous
  • anonymous
listen to that person ^
anonymous
  • anonymous
@fakeee I'm confused
anonymous
  • anonymous
I am saying that f(x) is an even function, if it satisfies f(a)=f(-a) for any value of a. for example, you have to have f(1)=f(-1)
anonymous
  • anonymous
in your options, there is only one such function that satisfies f(-a)=f(a) which on do you think it is and why?
anonymous
  • anonymous
So it's A. g(x) = (x – 1)2 + 1 ?
anonymous
  • anonymous
plug in a and -a into each option and set them equivalent to each other: (like this ) \((a-1)^2+1=(-a-1)^2+1\) \(2(a)^2+1=2(-a)^2+1\) \(4(a)+2=4(-a)+2\) \(2(a)=2(-a)\)
anonymous
  • anonymous
can you tell me now which is that function that satisfies f(a)=f(-a) ?
anonymous
  • anonymous
So I plug in a for x ?
anonymous
  • anonymous
Nvm I figured it out thanks you

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