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anonymous

  • one year ago

Which of the following is an even function? g(x) = (x – 1)2 + 1 g(x) = 2x2 + 1 g(x) = 4x + 2 g(x) = 2x

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  1. anonymous
    • one year ago
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    @Lokid

  2. anonymous
    • one year ago
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    @Kash_TheSmartGuy

  3. anonymous
    • one year ago
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    sorry i don't rember :/

  4. anonymous
    • one year ago
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    f(-a)=f(a) then f(x) is an even function

  5. anonymous
    • one year ago
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    listen to that person ^

  6. anonymous
    • one year ago
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    @fakeee I'm confused

  7. anonymous
    • one year ago
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    I am saying that f(x) is an even function, if it satisfies f(a)=f(-a) for any value of a. for example, you have to have f(1)=f(-1)

  8. anonymous
    • one year ago
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    in your options, there is only one such function that satisfies f(-a)=f(a) which on do you think it is and why?

  9. anonymous
    • one year ago
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    So it's A. g(x) = (x – 1)2 + 1 ?

  10. anonymous
    • one year ago
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    plug in a and -a into each option and set them equivalent to each other: (like this ) \((a-1)^2+1=(-a-1)^2+1\) \(2(a)^2+1=2(-a)^2+1\) \(4(a)+2=4(-a)+2\) \(2(a)=2(-a)\)

  11. anonymous
    • one year ago
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    can you tell me now which is that function that satisfies f(a)=f(-a) ?

  12. anonymous
    • one year ago
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    So I plug in a for x ?

  13. anonymous
    • one year ago
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    Nvm I figured it out thanks you

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