anonymous
  • anonymous
can u check my answer please?
Algebra
schrodinger
  • schrodinger
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anonymous
  • anonymous
UsukiDoll
  • UsukiDoll
if my x = 0 my y = 10 so it's a very high point |dw:1434432323545:dw|
UsukiDoll
  • UsukiDoll
|dw:1434432342625:dw| because typing 0 to 10 takes too much time

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UsukiDoll
  • UsukiDoll
|dw:1434432380989:dw|
UsukiDoll
  • UsukiDoll
I keep on getting my terminology mixed up even though I am graphing correctly
anonymous
  • anonymous
so is A correct?
UsukiDoll
  • UsukiDoll
since the vertex is the highest point at (0,10) I have a parabola that opens in the downward direction.
UsukiDoll
  • UsukiDoll
yeah but I also found a shortcut Apparently for ax^2+bx+c if your a>0 it should open upward so the vertex point is down if your a <0 the parabola should open downward so the vertex point is up
UsukiDoll
  • UsukiDoll
your a was -4, so -4<0 implies that parabola is opening downwards.
UsukiDoll
  • UsukiDoll
I mean't -3 ... oh man I'm tired x_)
UsukiDoll
  • UsukiDoll
-3<0 since a = -3 parabola is opening downward
anonymous
  • anonymous
so i was right with A?
UsukiDoll
  • UsukiDoll
yes
anonymous
  • anonymous
can u check 1 more?

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