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anonymous

  • one year ago

can u check my answer please?

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  1. anonymous
    • one year ago
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  2. UsukiDoll
    • one year ago
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    if my x = 0 my y = 10 so it's a very high point |dw:1434432323545:dw|

  3. UsukiDoll
    • one year ago
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    |dw:1434432342625:dw| because typing 0 to 10 takes too much time

  4. UsukiDoll
    • one year ago
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    |dw:1434432380989:dw|

  5. UsukiDoll
    • one year ago
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    I keep on getting my terminology mixed up even though I am graphing correctly

  6. anonymous
    • one year ago
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    so is A correct?

  7. UsukiDoll
    • one year ago
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    since the vertex is the highest point at (0,10) I have a parabola that opens in the downward direction.

  8. UsukiDoll
    • one year ago
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    yeah but I also found a shortcut Apparently for ax^2+bx+c if your a>0 it should open upward so the vertex point is down if your a <0 the parabola should open downward so the vertex point is up

  9. UsukiDoll
    • one year ago
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    your a was -4, so -4<0 implies that parabola is opening downwards.

  10. UsukiDoll
    • one year ago
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    I mean't -3 ... oh man I'm tired x_)

  11. UsukiDoll
    • one year ago
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    -3<0 since a = -3 parabola is opening downward

  12. anonymous
    • one year ago
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    so i was right with A?

  13. UsukiDoll
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    can u check 1 more?

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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