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anonymous

  • one year ago

Suppose a magnetic field of 0.20 T is applied to the area within a circular loop of wire. The strength of the field is then changed to 0.10 T. By what factor is the magnetic flux changed? 1/2 , 1/4 , 2 , or 4 ? :/

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  1. Michele_Laino
    • one year ago
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    before variation, the magnetic flux is: 0.20 * S, where S is the area enclose by the circular loop after the variation, the magnetic flux is: 0.10*S so the magnetic flkux changing is: \[\Delta \Phi = 0.2S - 0.1S = 0.1S\]

  2. rvc
    • one year ago
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    do you know the relation between the two?

  3. Michele_Laino
    • one year ago
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    and the requested ratio is: \[\frac{{{\Phi _2}}}{{{\Phi _1}}} = \frac{{0.1S}}{{0.2S}} = ...\]

  4. anonymous
    • one year ago
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    ohh okay! so then we get 1/2 as our solution?

  5. Michele_Laino
    • one year ago
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    yes! I think so!

  6. anonymous
    • one year ago
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    yay! thanks!!:D

  7. Michele_Laino
    • one year ago
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    :)

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