anonymous
  • anonymous
Suppose a magnetic field of 0.20 T is applied to the area within a circular loop of wire. The strength of the field is then changed to 0.10 T. By what factor is the magnetic flux changed? 1/2 , 1/4 , 2 , or 4 ? :/
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Michele_Laino
  • Michele_Laino
before variation, the magnetic flux is: 0.20 * S, where S is the area enclose by the circular loop after the variation, the magnetic flux is: 0.10*S so the magnetic flkux changing is: \[\Delta \Phi = 0.2S - 0.1S = 0.1S\]
rvc
  • rvc
do you know the relation between the two?
Michele_Laino
  • Michele_Laino
and the requested ratio is: \[\frac{{{\Phi _2}}}{{{\Phi _1}}} = \frac{{0.1S}}{{0.2S}} = ...\]

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anonymous
  • anonymous
ohh okay! so then we get 1/2 as our solution?
Michele_Laino
  • Michele_Laino
yes! I think so!
anonymous
  • anonymous
yay! thanks!!:D
Michele_Laino
  • Michele_Laino
:)

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