## anonymous one year ago A 1.2 m wire carries a current of 10.0 A in a uniform magnetic field of magnitude of 0.050 T, as shown. Find the magnitude of the magnetic force on the wire. A. 0.42 N B. 0.60 N C. 0.060 N D. 0.006 N will draw image inside! :)

1. anonymous

|dw:1434436221235:dw|

2. Michele_Laino

since magnetic field and current are perpendicular each other, then the magnitude of the magnetic force F, is: $\Large F = ILB = 10 \times 1.2 \times 0.050 = ...Newtons$

3. rvc

multiply all the numbers F = BIL

4. anonymous

0.6! so the solution is choice B?

5. rvc

yep

6. Michele_Laino

that's right!

7. anonymous

yay! thanks!:)

8. Michele_Laino

:)