anonymous
  • anonymous
a 1.2 m long steel rod moves through a uniform magnetic field of 0.020 T at 20 m/s. What emf is induced between the two ends of the steel rod? A. 0.60 V B. 0.48 V C. 0.36 V D. 0.50 V *will draw inside!
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1434439190034:dw|
anonymous
  • anonymous
the inner circles are shaded darker :)
Michele_Laino
  • Michele_Laino
inside our rod the Lorentz force is acting on the free electrons: |dw:1434439163697:dw|

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anonymous
  • anonymous
ok!
Michele_Laino
  • Michele_Laino
at the equilibrium thos forces, the lorentz force and the electrostatic force have the same magnitude, so we can write: \[\Large eE = evB\] and then: \[\Large V = vBL\] being L the length of the rod, and V the emf
anonymous
  • anonymous
ok! what do we plug in? :/
Michele_Laino
  • Michele_Laino
\[V = vBL = 20 \times 0.02 \times 1.2 = ...volts\]
anonymous
  • anonymous
we get 0.48! so choice B is the solutoin?
Michele_Laino
  • Michele_Laino
yes! that's right!
anonymous
  • anonymous
yay!thanks!! okay, last one!!:)
Michele_Laino
  • Michele_Laino
ok! :)

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