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Mindblast3r

  • one year ago

help me pls

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  1. mindblast3r
    • one year ago
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  2. mindblast3r
    • one year ago
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    how does the first equation turn into the second one?

  3. rvc
    • one year ago
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    \[\rm \sqrt{x}~can~also~be~written~as~x^{\frac{1}{2}}\] \[\rm \sqrt{x}~.\sqrt{x}~also~be~written~as~x^{\frac{1}{2}}~.x^{\frac{1}{2}}-->x^{\frac{1}{2}+\frac{1}{2}}-->x^{1}-->x\]

  4. rvc
    • one year ago
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    so \(\Large\rm\sqrt{x}~.\sqrt{x}=x\)

  5. mindblast3r
    • one year ago
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    ohh i get it now!

  6. mindblast3r
    • one year ago
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    \[\sqrt{3}\times \sqrt{3}=3\]

  7. wolf1728
    • one year ago
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    Just multiply it out [36 / sqrt(3)] * sqrt(3)/sqrt(3) = The sqrt(3) * sqrt(3) = 3 So, that equals [36 * sqrt(3)] / 3

  8. rvc
    • one year ago
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    correct @Mindblast3r :)

  9. wolf1728
    • one year ago
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    Hi MindBlast I neatened up my answer and deleted that earlier answer.

  10. mindblast3r
    • one year ago
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    wow you guys really helped a lot, and yea i saw @wolf1728

  11. rvc
    • one year ago
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    All The Best :)

  12. wolf1728
    • one year ago
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    Okay mind blast

  13. wolf1728
    • one year ago
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    Heck, I think rvc did some good work too!

  14. mindblast3r
    • one year ago
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    you both did.

  15. wolf1728
    • one year ago
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    Thanks - that's why I awarded him my own medal. And thank you mind blast

  16. mindblast3r
    • one year ago
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    NP

  17. wolf1728
    • one year ago
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    okay - time to go c ya

  18. mindblast3r
    • one year ago
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    cya

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