DominantVampire
  • DominantVampire
URGENT HELP
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
DominantVampire
  • DominantVampire
a block of mass 12 kg is released from rest om a friction-less incline of the angle theta=30 below the block is a spring having spring constant 10^4 N/m. the block stops momentarily when it compresses the spring by 4 cm. how far does the block move down the incline from its rest position to this stopping point
DominantVampire
  • DominantVampire
does anybody know
DominantVampire
  • DominantVampire
@ganeshie8 @Compassionate @mathmate @mathmath333

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DominantVampire
  • DominantVampire
just*
DominantVampire
  • DominantVampire
i asked this sol. many times but each time the FORMULA is different
DominantVampire
  • DominantVampire
q*
DominantVampire
  • DominantVampire
irish boy come to physics department in my Q which you already answered but what youve answered is energy not the distance, please look other solutions too, i am getting diff. ans
anonymous
  • anonymous
why urgent?
IrishBoy123
  • IrishBoy123
there does seem to be some confusion about this. the first thing you need to do always is to draw it - and yes i could probably do this in my head but i would still always sketch it in outline just to be sure. that not only aids communications between you and others but will help you get the problem clear in your mind and it will also be a place to define variables such as vertical distance and distance along the slope - which are important here. you should do that first using the "Draw" widget that OS provides after that we can work through it.
DominantVampire
  • DominantVampire
oka
DominantVampire
  • DominantVampire
|dw:1434455352074:dw|
IrishBoy123
  • IrishBoy123
yeah!! |dw:1434455454721:dw| this is what i mean by adding in other data. make sense?
DominantVampire
  • DominantVampire
yes it does
IrishBoy123
  • IrishBoy123
so "frictionless" means no energy lost to friction/heat, yes? that means we are looking at loss of grav potential energy of block which converts to potential energy in spring. simplest way to do it. is that what you are after?
DominantVampire
  • DominantVampire
yes that's what it mean and that's what i'm after
IrishBoy123
  • IrishBoy123
why not makes it easy for now just by calculating the energy in the spring when it is compressed 4cm. just work that out.
DominantVampire
  • DominantVampire
1/2kx^2?
IrishBoy123
  • IrishBoy123
yes
DominantVampire
  • DominantVampire
oka so this is the first step? 1/2 (10^4)(4)^2
IrishBoy123
  • IrishBoy123
mmmm. units? maybe this is where you are going wrong?
DominantVampire
  • DominantVampire
convert 4 cm into mterers so 0.04 m the ans i get K.E= 8J
DominantVampire
  • DominantVampire
joule
IrishBoy123
  • IrishBoy123
|dw:1434456031864:dw|
DominantVampire
  • DominantVampire
i said that
IrishBoy123
  • IrishBoy123
8J here too all good so far now that is the grav potential energy the block lost by sliding down the slope. we need now calc h -- see the diagram. know how to?
DominantVampire
  • DominantVampire
U= mgh ? perhaps the P.E
DominantVampire
  • DominantVampire
i dont know, sighs, thats where i get confused perhaps we use energy conservation formula
IrishBoy123
  • IrishBoy123
looks good. do the sums and we can compare results. do you use g = 10 or 9.8?
DominantVampire
  • DominantVampire
9.8 to be exact
DominantVampire
  • DominantVampire
how to find h? where U= mgh U is??
DominantVampire
  • DominantVampire
we might resolve into its components ?
DominantVampire
  • DominantVampire
mgh sin theta
IrishBoy123
  • IrishBoy123
look at diagram where i marked "h" in. that is what we want. make sense? mgh = 8J
DominantVampire
  • DominantVampire
oh so U=K i see (12)(9.8)h= 8 so h is 0.06 m
IrishBoy123
  • IrishBoy123
check your calculator: 0.06 m ? i get 0.068 which is closer to 0.07.
DominantVampire
  • DominantVampire
yes yes it was
IrishBoy123
  • IrishBoy123
|dw:1434456513348:dw| so this is where we are, and another litle sketch to make sure we understand what is happening do you agree with this?
DominantVampire
  • DominantVampire
yes it right
IrishBoy123
  • IrishBoy123
and question asks: "how far does the block move down the incline from its rest position to this stopping point " do you see it? what is the answer?
DominantVampire
  • DominantVampire
mmm no, i dont. im sorry
DominantVampire
  • DominantVampire
the answer is h?
IrishBoy123
  • IrishBoy123
|dw:1434456741787:dw| to lose 8J of PE, the block had to fall 0.068m vertically. that involved travelling distance d down the slope. so this now becomes a simple trig problem....
IrishBoy123
  • IrishBoy123
do you know trigonometry? sin, cos, tan and the rest?
DominantVampire
  • DominantVampire
oh yes im sorry
IrishBoy123
  • IrishBoy123
you have the opposite, you want the hypoteneuse, sohcahtoa....
IrishBoy123
  • IrishBoy123
we're close, are you still there or wanna finish later?
DominantVampire
  • DominantVampire
im sorry there was a power cut
IrishBoy123
  • IrishBoy123
well, fire away. use trig and get d from h = 0.068 and angle = 30degrees
DominantVampire
  • DominantVampire
it would be dsin30=h so 0.07/sin30
DominantVampire
  • DominantVampire
is it correct
IrishBoy123
  • IrishBoy123
yes, in cm, d = 13.6cm
DominantVampire
  • DominantVampire
0.136 m
DominantVampire
  • DominantVampire
i saw this ans. somewhere else too, let me show you, please do visit
DominantVampire
  • DominantVampire
@IrishBoy123 thankyou so so much

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