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anonymous
 one year ago
In triangle ABC, a = 3, b = 5, and c = 7. Find the approximate value of angle A.
anonymous
 one year ago
In triangle ABC, a = 3, b = 5, and c = 7. Find the approximate value of angle A.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok use the quadratic formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.022° 38° 142° 158° these are the answer choices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ b+\sqrt{(b)4(a)(c)} }{ ?2(a) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im still not understanding

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0In geometry, it always helps to draw a diagram according to the given information. dw:1434459130639:dw

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0cosine rule says: \(a^2=b^2+c^22(b)(c) cos(A)\) from which you can solve for cos(A): \(\Large cos(A)=\frac{b^2+c^2a^2}{2bc}\) So you can substitute a,b,c into the equation and solve for angle A.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what do you get when you that because i keepp getting something different

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@jcwilliams504 What have you done so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i plugged in everything but i dont know how to solve

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Do you know the values of a, b, and c?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Good, so what did you get for: \(\Large \frac{b^2+c^2a^2}{2bc}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0That's correct. You can find the angle A by solving cos(A)=65/70=13/14 or A = cos\(^{1}\)(13/14)
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