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anonymous
 one year ago
Help me Simplify 9log9(7)
anonymous
 one year ago
Help me Simplify 9log9(7)

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Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0\[\log_{a}B^n=nlog_{a} B\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.09(log(9))(7) 60.117278 if this is wrong fell free to correct me

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0\(\log_ba = \dfrac{\ln a}{\ln b}\), I guess.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0@aloud That's not simplifying though.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0I don't think you should move 9 to exponent in log. Doesn't seem like "simplifying" to me.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Not sure, To me, your expression is already simplified. Unless you can do something about base.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0after reworking it i get 7

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0Neither is transforming into a neiperian logarithm with a denominator which complicates the domain.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0"complicates the domain" Do you even know what domain is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Guys please i need help with this not argueing

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0You can hardly simplify a logarithm, you are very far from lecturing me.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Tell me, genius. How does simplifying logarithm change its domain?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Please help me......

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434463121313:dw

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0In spite of geerky, who clearly hasn't mastered basic algebra yet. We will use the property I stated above: \[\log_{a} B^n=nlog_{a} B\] So, for the problem: \[9\log_{9} (7)\] We'll just take it to the exponent: \[\log_{9}(7)^9 \] That would be a more simplified version, because later on, you'll learn that log(a)B^n is a more simplified way of expressing a logarithm because of the very definition: \[\log_{a}b^n=c <=>a^c=b^n\]

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0We are simplifying a expression, not equation. So turn it into exponential form wouldn't work out well. Plus it's not \(\log_9(7)^9\), it's \(\log_9(7^9)\)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Multiplication looks simplified to me than exponent. So as far as I concern, given expression is pretty much already simplified. Exactly what kind of form are you asked to simplify into? @maryah.g.osborn

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0hahahaha... As I said, do as you deem fit, I have no desire to argue with unmature people.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Clearly because you don't want to make yourself look any more fool.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1relax friends i think the question looks terrible because of not using latex, i think it should be \[\large 9^{\log_9 7}\] @maryah.g.osborn please confirm if the expression looks as above or attach a screenshot if possible
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