## anonymous one year ago Help me Simplify 9log9(7)

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1. Owlcoffee

$\log_{a}B^n=nlog_{a} B$

2. anonymous

9(log(9))(7) 60.117278 if this is wrong fell free to correct me

3. geerky42

$$\log_ba = \dfrac{\ln a}{\ln b}$$, I guess.

4. geerky42

@aloud That's not simplifying though.

5. anonymous

I i think it is 9^7

6. geerky42

I don't think you should move 9 to exponent in log. Doesn't seem like "simplifying" to me.

7. geerky42

Not sure, To me, your expression is already simplified. Unless you can do something about base.

8. anonymous

after reworking it i get 7

9. Owlcoffee

Neither is transforming into a neiperian logarithm with a denominator which complicates the domain.

10. geerky42

"complicates the domain" Do you even know what domain is?

11. anonymous

Guys please i need help with this not argueing

12. Owlcoffee

You can hardly simplify a logarithm, you are very far from lecturing me.

13. geerky42

Tell me, genius. How does simplifying logarithm change its domain?

14. geerky42

@ganeshie8

15. anonymous

16. geerky42

|dw:1434463121313:dw|

17. Owlcoffee

In spite of geerky, who clearly hasn't mastered basic algebra yet. We will use the property I stated above: $\log_{a} B^n=nlog_{a} B$ So, for the problem: $9\log_{9} (7)$ We'll just take it to the exponent: $\log_{9}(7)^9$ That would be a more simplified version, because later on, you'll learn that log(a)B^n is a more simplified way of expressing a logarithm because of the very definition: $\log_{a}b^n=c <=>a^c=b^n$

18. geerky42

We are simplifying a expression, not equation. So turn it into exponential form wouldn't work out well. Plus it's not $$\log_9(7)^9$$, it's $$\log_9(7^9)$$

19. geerky42

Multiplication looks simplified to me than exponent. So as far as I concern, given expression is pretty much already simplified. Exactly what kind of form are you asked to simplify into? @maryah.g.osborn

20. Owlcoffee

Do as you desire...

21. geerky42
22. geerky42

23. Owlcoffee

hahahaha... As I said, do as you deem fit, I have no desire to argue with unmature people.

24. geerky42

Clearly because you don't want to make yourself look any more fool.

25. ganeshie8

relax friends i think the question looks terrible because of not using latex, i think it should be $\large 9^{\log_9 7}$ @maryah.g.osborn please confirm if the expression looks as above or attach a screenshot if possible