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anonymous
 one year ago
Given: tangent to Circle O.
If m = 140°, then A =
70
110
140
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anonymous
 one year ago
Given: tangent to Circle O. If m = 140°, then A = 70 110 140 http://assets.openstudy.com/updates/attachments/53739855e4b0530e83f03f38tootsi1231400084606214group179.gif

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geerky42
 one year ago
Best ResponseYou've already chosen the best response.0m = 140° ? Do you mean \(m\angle C=140^\text o\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, its m DB with an arch over that= 140

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0I think that refers to arc DAB (minor arc), right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0In that case, then angle half the 140

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, because DB = 140 DAB = 140?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I am on laptop. What I am trying to say is that given the information, we can see that angle C is half the measure of arc BD dw:1434465275082:dw

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Then given ABCD is inscribed in circle, we know that sum of opposite angles is always 180, right?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Okay, then we have \(m\angle A+m\angle C = 180^\text o\)

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0we figured out that C is 70.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, i got the answer. my teacher came by and just gave me it. thank you for your time!!! i understand it better now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i had rather her explain it to me though

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0ok, answer is 110, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats what she said. thanks again!
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