## anonymous one year ago Given: tangent to Circle O. If m = 140°, then A = 70 110 140 http://assets.openstudy.com/updates/attachments/53739855e4b0530e83f03f38-tootsi123-1400084606214-group179.gif

1. anonymous

@ganeshie8

2. anonymous

@geerky42

3. anonymous

@freckles

4. geerky42

m = 140° ? Do you mean $$m\angle C=140^\text o$$

5. anonymous

sorry, its m DB with an arch over that= 140

6. anonymous

7. anonymous

would it be 140?

8. geerky42

I think that refers to arc DAB (minor arc), right?

9. anonymous

right

10. geerky42

In that case, then angle half the 140

11. anonymous

so, because DB = 140 DAB = 140?

12. geerky42

Sorry I am on laptop. What I am trying to say is that given the information, we can see that angle C is half the measure of arc BD |dw:1434465275082:dw|

13. geerky42

Then given ABCD is inscribed in circle, we know that sum of opposite angles is always 180, right?

14. geerky42

15. anonymous

right

16. anonymous

and yes

17. geerky42

Okay, then we have $$m\angle A+m\angle C = 180^\text o$$

18. geerky42

we figured out that C is 70.

19. geerky42

Right?

20. anonymous

right

21. anonymous

wait, i got the answer. my teacher came by and just gave me it. thank you for your time!!! i understand it better now

22. anonymous

i had rather her explain it to me though

23. geerky42

24. geerky42

ok great!

25. anonymous

thats what she said. thanks again!

26. geerky42

ok no problem