m = 140° ? Do you mean \(m\angle C=140^\text o\)
sorry, its m DB with an arch over that= 140
would it be 140?
I think that refers to arc DAB (minor arc), right?
In that case, then angle half the 140
so, because DB = 140 DAB = 140?
Sorry I am on laptop. What I am trying to say is that given the information, we can see that angle C is half the measure of arc BD |dw:1434465275082:dw|
Then given ABCD is inscribed in circle, we know that sum of opposite angles is always 180, right?
Do you follow me?
Okay, then we have \(m\angle A+m\angle C = 180^\text o\)
we figured out that C is 70.
wait, i got the answer. my teacher came by and just gave me it. thank you for your time!!! i understand it better now
i had rather her explain it to me though
ok, answer is 110, right?
thats what she said. thanks again!
ok no problem