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anonymous
 one year ago
HELP?? WILL MEDAL, AND FAN
Find the xintercepts of the parabola with vertex (1,108) and yintercept (0,105).
Write your answer in this form: (x1,y1),(x2,y2).
If necessary, round to the nearest hundredth.
anonymous
 one year ago
HELP?? WILL MEDAL, AND FAN Find the xintercepts of the parabola with vertex (1,108) and yintercept (0,105). Write your answer in this form: (x1,y1),(x2,y2). If necessary, round to the nearest hundredth.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have the answer so far, can anyone just help me get the points out of y=3x^2+2x107???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0long time since i done these...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0general form is y = ax^2 + bx + c when x = 0 , y = 105 so c = 105

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x coordinate of the vertex = b / 2a = 1 the y coordinate of the vertex = 108 so 108 = a*1^2 + b  105

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so b = 2a and 108 = a + b  105 a + b = 3 substitute b = 2a in the above: a  2a = 3 a = 3 a = 3 now finding b: b = 3 3 = 6 so equation is 3x^2  6x  105 = 0 solve to find the x intercepts: (3x  21)(x + 5 ) = 0 x = 7 , 5 x intercepts are 7 and 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you, but reverse the signs and its correct
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