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you need to isolate x's from constant terms (this is how we solve equations) Thus, divide by 3/4 => x-12=16 x=28
What do you need help with?
Is it the same thing as for x?
do you know what to do 1st?
No you isolate the variable last after you have everything else away from it Ex. 2x - 4 = 4 To love this equation you would first +4 to both sides in order to get 2x=8 then you would divide 2 from both sides to get the answer of x=4
A fraction where?
x = 28
We are on a different problem now
oh what is it
3/4y-12=12 solve for y
Trying to get her to understand when to add or multiply or whatever 1st
y in (-oo:+oo) (3/4)*y = 12 // - 12 (3/4)*y-12 = 0 3/4*y-12 = 0 // + 12 3/4*y = 12 // : 3/4 y = 12/3/4 y = 16 y = 16
I think you did it wrong why is there a 0 it is supposed to be 12
So whats the answer?
(3/4)y-12=12 +12+12 (3/4)y = 24 Divide by the reciprocal of 3/4 which is 4/3 which then you would really be multiplying 4/3•24 which = 32
So y = 32
So the answer is 32?
and if you plug 32 for y you should get 12
okay thanks both of you guys :)