anonymous
  • anonymous
MEDALLLL PLZZ HELP! SOLVE FOR X: 3/4(x-12)=12
Mathematics
chestercat
  • chestercat
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P0sitr0n
  • P0sitr0n
you need to isolate x's from constant terms (this is how we solve equations) Thus, divide by 3/4 => x-12=16 x=28
anonymous
  • anonymous
So the answer is 28 @P0sitr0n
anonymous
  • anonymous
Can you help me with 1 more problem? @P0sitr0n

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anonymous
  • anonymous
What do you need help with?
anonymous
  • anonymous
3/4y-12=12 solve for y? @taylorz115820
anonymous
  • anonymous
Is it the same thing as for x?
anonymous
  • anonymous
Isolate y
anonymous
  • anonymous
do you know what to do 1st?
anonymous
  • anonymous
divide?
anonymous
  • anonymous
No you isolate the variable last after you have everything else away from it Ex. 2x - 4 = 4 To love this equation you would first +4 to both sides in order to get 2x=8 then you would divide 2 from both sides to get the answer of x=4
anonymous
  • anonymous
Make sense?
anonymous
  • anonymous
yea but I always get confused whenever there's a fraction? @taylorz115820
anonymous
  • anonymous
A fraction where?
anonymous
  • anonymous
x = 28
anonymous
  • anonymous
We are on a different problem now
anonymous
  • anonymous
oh what is it
anonymous
  • anonymous
3/4y-12=12 solve for y
anonymous
  • anonymous
Trying to get her to understand when to add or multiply or whatever 1st
anonymous
  • anonymous
y in (-oo:+oo) (3/4)*y = 12 // - 12 (3/4)*y-12 = 0 3/4*y-12 = 0 // + 12 3/4*y = 12 // : 3/4 y = 12/3/4 y = 16 y = 16
anonymous
  • anonymous
I think you did it wrong why is there a 0 it is supposed to be 12
anonymous
  • anonymous
hold on
anonymous
  • anonymous
So whats the answer?
anonymous
  • anonymous
(3/4)y-12=12 +12+12 (3/4)y = 24 Divide by the reciprocal of 3/4 which is 4/3 which then you would really be multiplying 4/3•24 which = 32
anonymous
  • anonymous
So y = 32
anonymous
  • anonymous
So the answer is 32?
anonymous
  • anonymous
Thanks
anonymous
  • anonymous
and if you plug 32 for y you should get 12
anonymous
  • anonymous
yea
anonymous
  • anonymous
okay thanks both of you guys :)

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