What is the perimeter of the figure to the nearest hundredth of a centimeter?
A.
24.56 cm
B.
18.28 cm
C.
16 cm
D.
14.28 cm

- anonymous

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- katieb

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- anonymous

http://static.k12.com/calms_media/media/1419000_1419500/1419360/1/b69e6f0436c6372513cf1e14b305f60a42b76b33/MS_PA_130922_171132.jpg

- anonymous

What is your understanding of this question?

- anonymous

im not sure but i think the answer is c

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## More answers

- anonymous

Okay.. let's see if you were correct as we go along.
Now, this shape has two figures:
1. A semi circle
2. A square

- anonymous

yeah okay

- anonymous

You need to find the perimeter of each individual shape then add them together.

- anonymous

What is the perimeter of the square?

- anonymous

okay

- anonymous

16?

- anonymous

Correct! Now, we can immediately eliminate C and D because the perimeter of the total figure will be GREATER than 16 since we haven't figured out the perimeter of the circle yet.

- anonymous

ohh okay

- anonymous

Now, remember last thread when I helped you figure out the perimeter of the semicircle?
Try figuring it out :)

- anonymous

okay

- anonymous

Remember: Circumference = 2πr or πd

- anonymous

oka

- anonymous

@Aureyliant Since it is a semi circle she could just use the equation πr. Am I correct?

- anonymous

Yup! I was just about t mention that :) @taylorz115820

- anonymous

b?

- anonymous

Lol

- anonymous

Tell me your explanation.
What was the circumference you got for this SEMI CIRCLE?

- anonymous

I need help!?!?!

- anonymous

?

- anonymous

Why are you multiplying it by 4?
You need to add the circumference of this semi circle to the perimeter of the square (16 cm)

- anonymous

idk

- anonymous

/

- anonymous

Please don't spam @tray15

- anonymous

|dw:1434472229049:dw|

- anonymous

There you go basically all you need right there

- anonymous

Good job @Aureyliant

- anonymous

Something isn't right though. A normal circle's circumference is = 2πr or πd
Even though this is a semi circle, the diameter will remain constant.
Though the final answer is A.

- anonymous

What you did was right a normal circle is 2πr so if you want half of that you simply don't "need" the 2 anymore

- anonymous

|dw:1434547080894:dw|

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