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I will take a look
1. A grain silo is shown below: What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22 over 7 for pi. My answer: 34,597 ft^3
If the height goes al the way up to the top of the semi circle which I can't tell then the answer is wrong because you still have to account for the volume of the half circle
That's okay, I'll figure that one out. 2. The radius of the cone is 1.5 inches, and its height is 3 inches. If the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice? My answer: 7.07 in^3
The answer to the 1st one would be 35,669
That is adding the volume of the semicircle
Oh I see.
2/3 pi r^3 is the equation for volume of a semicircle so you add the answer of that to your original answer to get my answer
So this is what we have
Yes and I used V=πr2h/3
So what we need to do is find the volume of the cone then subtract the volume of the gumboil
Oh 7.00 in^3
The volume of the cone is \[\approx7.07\]
Now we need to subtract the volume of the gumball
That equation is \[V=4/3πr^3\]
so if we plug .5 into r what do you get?
We get \[\approx0.52\]
So all you have to do is 7.07-.52 and you will have your answer