Unofficialllyy
  • Unofficialllyy
Can someone check my 5 Geometry questions? Thank you in advance!
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Sure
anonymous
  • anonymous
I will take a look
Unofficialllyy
  • Unofficialllyy
1. A grain silo is shown below: What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22 over 7 for pi. My answer: 34,597 ft^3
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anonymous
  • anonymous
If the height goes al the way up to the top of the semi circle which I can't tell then the answer is wrong because you still have to account for the volume of the half circle
Unofficialllyy
  • Unofficialllyy
That's okay, I'll figure that one out. 2. The radius of the cone is 1.5 inches, and its height is 3 inches. If the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice? My answer: 7.07 in^3
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anonymous
  • anonymous
The answer to the 1st one would be 35,669
anonymous
  • anonymous
That is adding the volume of the semicircle
Unofficialllyy
  • Unofficialllyy
Oh I see.
anonymous
  • anonymous
2/3 pi r^3 is the equation for volume of a semicircle so you add the answer of that to your original answer to get my answer
Unofficialllyy
  • Unofficialllyy
Yup
anonymous
  • anonymous
|dw:1434474137390:dw|
anonymous
  • anonymous
So this is what we have
Unofficialllyy
  • Unofficialllyy
Yes and I used V=πr2h/3
anonymous
  • anonymous
So what we need to do is find the volume of the cone then subtract the volume of the gumboil
anonymous
  • anonymous
gumball*
Unofficialllyy
  • Unofficialllyy
Oh 7.00 in^3
anonymous
  • anonymous
1 sec
Unofficialllyy
  • Unofficialllyy
Okay
anonymous
  • anonymous
The volume of the cone is \[\approx7.07\]
anonymous
  • anonymous
Now we need to subtract the volume of the gumball
Unofficialllyy
  • Unofficialllyy
Right.
anonymous
  • anonymous
That equation is \[V=4/3πr^3\]
anonymous
  • anonymous
so if we plug .5 into r what do you get?
anonymous
  • anonymous
We get \[\approx0.52\]
anonymous
  • anonymous
So all you have to do is 7.07-.52 and you will have your answer

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