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Unofficialllyy

  • one year ago

Can someone check my 5 Geometry questions? Thank you in advance!

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  1. anonymous
    • one year ago
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    Sure

  2. anonymous
    • one year ago
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    I will take a look

  3. Unofficialllyy
    • one year ago
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    1. A grain silo is shown below: What is the volume of grain that could completely fill this silo, rounded to the nearest whole number? Use 22 over 7 for pi. My answer: 34,597 ft^3

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  4. anonymous
    • one year ago
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    If the height goes al the way up to the top of the semi circle which I can't tell then the answer is wrong because you still have to account for the volume of the half circle

  5. Unofficialllyy
    • one year ago
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    That's okay, I'll figure that one out. 2. The radius of the cone is 1.5 inches, and its height is 3 inches. If the diameter of the bubble gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be filled with flavored ice? My answer: 7.07 in^3

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  6. anonymous
    • one year ago
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    The answer to the 1st one would be 35,669

  7. anonymous
    • one year ago
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    That is adding the volume of the semicircle

  8. Unofficialllyy
    • one year ago
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    Oh I see.

  9. anonymous
    • one year ago
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    2/3 pi r^3 is the equation for volume of a semicircle so you add the answer of that to your original answer to get my answer

  10. Unofficialllyy
    • one year ago
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    Yup

  11. anonymous
    • one year ago
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    |dw:1434474137390:dw|

  12. anonymous
    • one year ago
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    So this is what we have

  13. Unofficialllyy
    • one year ago
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    Yes and I used V=πr2h/3

  14. anonymous
    • one year ago
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    So what we need to do is find the volume of the cone then subtract the volume of the gumboil

  15. anonymous
    • one year ago
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    gumball*

  16. Unofficialllyy
    • one year ago
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    Oh 7.00 in^3

  17. anonymous
    • one year ago
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    1 sec

  18. Unofficialllyy
    • one year ago
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    Okay

  19. anonymous
    • one year ago
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    The volume of the cone is \[\approx7.07\]

  20. anonymous
    • one year ago
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    Now we need to subtract the volume of the gumball

  21. Unofficialllyy
    • one year ago
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    Right.

  22. anonymous
    • one year ago
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    That equation is \[V=4/3πr^3\]

  23. anonymous
    • one year ago
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    so if we plug .5 into r what do you get?

  24. anonymous
    • one year ago
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    We get \[\approx0.52\]

  25. anonymous
    • one year ago
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    So all you have to do is 7.07-.52 and you will have your answer

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