## anonymous one year ago What is the value of 19 + 5a^4 – 3b^2 when a = 2 and b = −4?

1. jagr2713

Hey what do you think we do first?

2. anonymous

hi @jagr2713 :D long time no see

3. anonymous

ok we multiply the exponets

4. anonymous

right?

5. jagr2713

correct spo what do we do with the 2^4

6. anonymous

Multiply the exponents? Do you mean apply the exponents?

7. anonymous

i think????

8. anonymous

do you guys have khans academy account?

9. anonymous

Yeah, I do. But how is that relevant to the question?

10. anonymous

so you can tell me where do i get videos from math n stuff

11. jagr2713

So we get 16 so we have 19+5*16-3(-4)^2 since the powers of 2 is even, the result will be positive 19+5*16-3*4^2 Now we sumplify 4^2 to 16 19+5*16-3*16 Can you use PEMDAS fro here

12. anonymous

256???

13. anonymous

...

14. jagr2713

no we simplify 5*16 to get 80 19+80-3*16 Now 3*16=48 19+80-48 solve from here

15. anonymous

$\large 19~+~(5 \times 16)~-~(3 \times 16)$

16. anonymous

51 (reacts to kid who says 21)

17. jagr2713

Use PEMDAS

18. jagr2713

Correct is 51!

19. anonymous

thx :D

20. jagr2713