anonymous
  • anonymous
What is the value of 19 + 5a^4 – 3b^2 when a = 2 and b = −4?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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jagr2713
  • jagr2713
Hey what do you think we do first?
anonymous
  • anonymous
hi @jagr2713 :D long time no see
anonymous
  • anonymous
ok we multiply the exponets

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anonymous
  • anonymous
right?
jagr2713
  • jagr2713
correct spo what do we do with the 2^4
anonymous
  • anonymous
Multiply the exponents? Do you mean apply the exponents?
anonymous
  • anonymous
i think????
anonymous
  • anonymous
do you guys have khans academy account?
anonymous
  • anonymous
Yeah, I do. But how is that relevant to the question?
anonymous
  • anonymous
so you can tell me where do i get videos from math n stuff
jagr2713
  • jagr2713
So we get 16 so we have 19+5*16-3(-4)^2 since the powers of 2 is even, the result will be positive 19+5*16-3*4^2 Now we sumplify 4^2 to 16 19+5*16-3*16 Can you use PEMDAS fro here
anonymous
  • anonymous
256???
anonymous
  • anonymous
...
jagr2713
  • jagr2713
no we simplify 5*16 to get 80 19+80-3*16 Now 3*16=48 19+80-48 solve from here
anonymous
  • anonymous
\[\large 19~+~(5 \times 16)~-~(3 \times 16)\]
anonymous
  • anonymous
51 (reacts to kid who says 21)
jagr2713
  • jagr2713
Use PEMDAS
jagr2713
  • jagr2713
Correct is 51!
anonymous
  • anonymous
thx :D
jagr2713
  • jagr2713
Glad to had helped today!
anonymous
  • anonymous
https://www.khanacademy.org/computer-programming/starwars-battle-on-the-death-star/5857960179924992 plz vote up to my game

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