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anonymous

  • one year ago

What is the value of 19 + 5a^4 – 3b^2 when a = 2 and b = −4?

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  1. jagr2713
    • one year ago
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    Hey what do you think we do first?

  2. anonymous
    • one year ago
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    hi @jagr2713 :D long time no see

  3. anonymous
    • one year ago
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    ok we multiply the exponets

  4. anonymous
    • one year ago
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    right?

  5. jagr2713
    • one year ago
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    correct spo what do we do with the 2^4

  6. anonymous
    • one year ago
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    Multiply the exponents? Do you mean apply the exponents?

  7. anonymous
    • one year ago
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    i think????

  8. anonymous
    • one year ago
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    do you guys have khans academy account?

  9. anonymous
    • one year ago
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    Yeah, I do. But how is that relevant to the question?

  10. anonymous
    • one year ago
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    so you can tell me where do i get videos from math n stuff

  11. jagr2713
    • one year ago
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    So we get 16 so we have 19+5*16-3(-4)^2 since the powers of 2 is even, the result will be positive 19+5*16-3*4^2 Now we sumplify 4^2 to 16 19+5*16-3*16 Can you use PEMDAS fro here

  12. anonymous
    • one year ago
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    256???

  13. anonymous
    • one year ago
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    ...

  14. jagr2713
    • one year ago
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    no we simplify 5*16 to get 80 19+80-3*16 Now 3*16=48 19+80-48 solve from here

  15. anonymous
    • one year ago
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    \[\large 19~+~(5 \times 16)~-~(3 \times 16)\]

  16. anonymous
    • one year ago
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    51 (reacts to kid who says 21)

  17. jagr2713
    • one year ago
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    Use PEMDAS

  18. jagr2713
    • one year ago
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    Correct is 51!

  19. anonymous
    • one year ago
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    thx :D

  20. jagr2713
    • one year ago
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    Glad to had helped today!

  21. anonymous
    • one year ago
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    https://www.khanacademy.org/computer-programming/starwars-battle-on-the-death-star/5857960179924992 plz vote up to my game

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