1. anonymous

1. Graph y = –2x2 + 6. Describe what you see. The graph looks like a parabola that is shifted up by around 6 units, and is stretched by a factor of 1/2. It is also pointing down, since the coefficient of -2x^2 is a negative. This question is complete, the next question is what I need help with graph y = (-1/10)x2 + 6. Describe what you see. How is what you observe here different from what you observed in part A?

2. anonymous

1356

3. anonymous

4. anonymous

1356?

5. Owlcoffee

Well, it is exactly the same way as you did the first time, but some things will change.

6. anonymous

So is this graphed shifted by 5 instead of 6? Or is it also 6?

7. anonymous

Im not sure how to graph that

8. Owlcoffee

Well, whenever you graph a second degree function, and it represents a parabola, it'll look like this: $y=Ax^2 + Bx + C$ This is pretty much the equation of the parabola and we can find the orientation, or the cancavity if you like, by looking at the sign that "A" has, if it is negative, the parabola opens downwards, if "A" is positive, it opens upwards. So, in the function you were given: $y=-\frac{ 1 }{ 10 }x^2+6$ "A" which in this case is "-1/10" is negative, so it opens downwards as well.

9. anonymous

Oh okay. Makes sense. Alright, give me a second.

10. anonymous

So when you say it opens downwards, you mean that it would look like a hill then?

11. Owlcoffee

yes, but there are more things you have to determine, like where it cuts the x-axis and where it cuts the y-axis.

12. anonymous

Alright, I think I can handle it from here. Thank you!

13. Owlcoffee

No problem.