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anonymous

  • one year ago

I WILL FAN AND MEDAL PLS HELP What is the value of the function when x = 1?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    someone pls help @Data_LG2 @DARTHVADER2900

  3. anonymous
    • one year ago
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    @Velocity1231

  4. anonymous
    • one year ago
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    @mukushla pls help me

  5. anonymous
    • one year ago
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    @Velocity1231 pls help

  6. anonymous
    • one year ago
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    @pooja195 can someone pls help me

  7. anonymous
    • one year ago
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    @Nnesha pls help me

  8. anonymous
    • one year ago
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    @mukushla

  9. anonymous
    • one year ago
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    @sdfgsdfgs pls can somone help

  10. anonymous
    • one year ago
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    @geerky42 pls help me

  11. sdfgsdfgs
    • one year ago
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    Can u read the graph? What is the value at x=1?

  12. anonymous
    • one year ago
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    i dunno thats what is confusing me

  13. sdfgsdfgs
    • one year ago
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    |dw:1434482751052:dw| for example in the graph above, when x=a, y=b ok?

  14. anonymous
    • one year ago
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    ok @sdfgsdfgs

  15. sdfgsdfgs
    • one year ago
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    do the same thing on YOUR graph plz :)

  16. anonymous
    • one year ago
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    ok

  17. sdfgsdfgs
    • one year ago
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    what did u find @ReganTommers ?

  18. anonymous
    • one year ago
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    im confused i dont know what to do

  19. anonymous
    • one year ago
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    @sdfgsdfgs

  20. sdfgsdfgs
    • one year ago
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    Read what I said in my last post with the graph, do u understand that - When x=a, the value of function y=b?

  21. anonymous
    • one year ago
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    like this just graphing @sdfgsdfgs

  22. anonymous
    • one year ago
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    im so confused @sdfgsdfgs

  23. sdfgsdfgs
    • one year ago
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    relax plz @ReganTommers :) u are getting close but it is not quite right.... will explain if u wuld calm down first

  24. anonymous
    • one year ago
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    im calm @sdfgsdfgs

  25. anonymous
    • one year ago
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    :)

  26. sdfgsdfgs
    • one year ago
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    hahahaa ok ;) notice in my drawing.... |dw:1434483324044:dw| following me so far?

  27. anonymous
    • one year ago
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    yes :) @sdfgsdfgs

  28. sdfgsdfgs
    • one year ago
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    So in ur sketch, u get the first part right - to draw the vertical line from x=1 but u missed in drawing the second line to find y....try again plz?

  29. anonymous
    • one year ago
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    |dw:1434483605115:dw|

  30. anonymous
    • one year ago
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    @sdfgsdfgs

  31. sdfgsdfgs
    • one year ago
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    |dw:1434483686908:dw| Funny u got the ans already n didnt know it :P

  32. anonymous
    • one year ago
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    the answer is 3? :)))

  33. anonymous
    • one year ago
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    y = ?

  34. sdfgsdfgs
    • one year ago
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    |dw:1434483762166:dw| Nope - u marked the right point but gave the wrong ans :(

  35. anonymous
    • one year ago
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    -2 ?

  36. anonymous
    • one year ago
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    @sdfgsdfgs

  37. anonymous
    • one year ago
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    pls help me @sdfgsdfgs

  38. anonymous
    • one year ago
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    may u pls help me @sdfgsdfgs

  39. sdfgsdfgs
    • one year ago
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    OK on your graph, please draw a straight line from x=1 until it hits the slanted line representing the function....

  40. anonymous
    • one year ago
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    like how

  41. sdfgsdfgs
    • one year ago
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    |dw:1434484195448:dw| like this

  42. anonymous
    • one year ago
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    ok @sdfgsdfgs |dw:1434484359318:dw|

  43. sdfgsdfgs
    • one year ago
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    |dw:1434484418578:dw|

  44. sdfgsdfgs
    • one year ago
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    |dw:1434484500592:dw|

  45. anonymous
    • one year ago
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    oh @sdfgsdfgs

  46. anonymous
    • one year ago
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    im kind of in a hurry @sdfgsdfgs can u explain the answer to me

  47. sdfgsdfgs
    • one year ago
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    |dw:1434484600055:dw|

  48. anonymous
    • one year ago
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    is -1 the answer?

  49. anonymous
    • one year ago
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    @sdfgsdfgs

  50. sdfgsdfgs
    • one year ago
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    BINGO :)

  51. anonymous
    • one year ago
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    thank u so much may u pls check another answer

  52. anonymous
    • one year ago
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    :) ok Alexa enrolled in an 8 week typing course. The graph shows her typing speed over the 8 week. Based on the graph, about how many words could she type per minute in the seventh week of the course?

  53. sdfgsdfgs
    • one year ago
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    Sure but only if it is easier than the last one.... or we may need help from @Nnesha

  54. anonymous
    • one year ago
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  55. anonymous
    • one year ago
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    yah haha

  56. anonymous
    • one year ago
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    @sdfgsdfgs is the answer 42

  57. sdfgsdfgs
    • one year ago
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    Same type of prob....in this case, u are looking for seven weeks. So x=7....

  58. sdfgsdfgs
    • one year ago
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    WOW @ReganTommers u are a FAST leaner!!!! :) 42 is very very very close..... but I think it may be 41 instead....

  59. anonymous
    • one year ago
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    A. 33 B. 36 C. 40 D. 42

  60. anonymous
    • one year ago
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    these r the choices :) @sdfgsdfgs

  61. sdfgsdfgs
    • one year ago
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    yup yup u are right @ReganTommers 42 is the right ans!

  62. anonymous
    • one year ago
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    OMGGGG U AREEEEE THHE BESTTT

  63. anonymous
    • one year ago
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    THANK U THANK U THANK U SO SO MUCH @sdfgsdfgs

  64. sdfgsdfgs
    • one year ago
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    U are welcome - hope u learnt something today @ReganTommers :)

  65. anonymous
    • one year ago
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    i really did i understand it more :-))))

  66. sdfgsdfgs
    • one year ago
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    Good - dats all we are trying to do here ;)

  67. anonymous
    • one year ago
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    thank u have a nice rest of the day everyone :))) @sdfgsdfgs and thank u

  68. anonymous
    • one year ago
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    bye :)

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