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anonymous
 one year ago
Find a quadratic model for the set of values: (2, 20), (0, 4), (4, 20). Show your work
anonymous
 one year ago
Find a quadratic model for the set of values: (2, 20), (0, 4), (4, 20). Show your work

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sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1Since u need to show ur work....the general quadratic model is y=ax^2 + bx + c Now we need to find the constants a, b, c ok?

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1U are given 3 points: (2, 20), (0, 4), (4, 20) So u can use them to solve for abc

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I suck at this and I don't get it

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1I will do the first one for u, @Raylynngrace :) y=ax^2 + bx + c for (2, 20) so 20 = a*(2)^2 + b*(2) + c 20 = 4a  2b + c ok?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay I get that now lol

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1Cool! Show me how u set up with the other two given points plz?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk if I did this right lol but for the next one I got y=ax^2+bx+c 4=a*(0)^2+b*(0) 4=ab+c

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1good try but u missed something...it should be like 4=a*(0)^2+b*(0) + c 4=0+0+c c=4 hey we found c already!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Least I tried lol can you help me with the last one

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1nope u do it plz? i will help of cus :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=ax^2+bx+c 20=a*(4)^2+b*(4) 20=16a+4b

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Did I get this one wrong to @sdfgsdfgs

sdfgsdfgs
 one year ago
Best ResponseYou've already chosen the best response.1@raylynngrace hahahaa u keep forgetting the c term....so it should be: 20=a*(4)^2+b*(4)+c 20=16a+4b+c now u got c=4 already and from the first point: 20 = 4a  2b + c U can solve for a and b :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Raylynngrace This will help you a bit. Try !! http://www.softschools.com/math/algebra/quadratic_functions/quadratic_function_with_three_points/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you both for your help @sdfgsdfgs @JoshKoikkara
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