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anonymous
 one year ago
From a boat on the lake, the angle of elevation to the top of a cliff is 15˚54'. If the base of the cliff is 967 feet from the boat, how high is the cliff (to the nearest foot)?
anonymous
 one year ago
From a boat on the lake, the angle of elevation to the top of a cliff is 15˚54'. If the base of the cliff is 967 feet from the boat, how high is the cliff (to the nearest foot)?

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Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434489196036:dw

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.1now what trigonometric function we will use here . If we look on the given data

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.1nope it would be cosine function cos theta = base / hypo:

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.1now put the value in the formula and get your answer

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.1Do it @clairvoyant1 by the help of calculator

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434539125033:dw then we can write: \[h = 967 \times \tan \left( {15.9} \right) = ...\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0since 15° 54' = 15.9 degrees
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