## anonymous one year ago How do you graph y=x^2-4x+3 I need the vertex, axis of symmetry, y and x axis as well will give medal

1. anonymous

complete the square on R.H.S.

2. anonymous

$y=x^2-4x+4-4+3=(x-2)^2-1$ $(x-2)^2=y+1$ it is an upward parabola with vertex (2,-1)

3. anonymous

axis of symetry is x-2=0 or x=2

4. anonymous

it cuts y-axis at (0,3)

5. anonymous

it cuts x-axis where y=0 $(x-2)^2=1,x-2=\pm1,x=?$

6. anonymous

Thank you

7. anonymous

yw