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anonymous
 one year ago
Let f(x) = 3x2 – x + 2 and g(x) = 5x2 – 1. Find f(g(x)).
anonymous
 one year ago
Let f(x) = 3x2 – x + 2 and g(x) = 5x2 – 1. Find f(g(x)).

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Will medal AND fan <3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0bec you have to substitute x for x you will get same equation so just substitute g(x) equation into f(x)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[f(g(x)) = 3(5x^21)(5x^21)+2\] notice we take the function g(x) and plug it everywhere there is an x in f(x) which means f(g(x)).

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[f(g(x)) = 3(5x^21)^2(5x^21)+2\] this is the proper one

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Now you may simplify it :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you wait until I finish so you can check my answer? :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Mhm, not quite, notice it's \[3(5x^21) \huge ^{2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. I don't understand

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[(5x^21)^2 \implies (5x^21)(5x^21)\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Awesome, now lets multiply it by 3 \[3(25x^410x^2+1)\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That's great :D, now we have \[75x^430x^2+3 (5x^21)+2\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Now simplify it a bit more

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Good one more step though, look for like terms

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup, we're done :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can I ask one more please? :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[f(g(x)) = 75x^435x^2+3\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Unless you want solutions to it as well, but I doubt it, since it's gross...and sure :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1And we are solving for x? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve the equation for the variable. Show each step of your solution process.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Sounds fun, any idea how to start

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And yes :) You know, the usual

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1See if you can do anything with the 4

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434493963942:dw so far so good right

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Now do you know how to deal with the square root

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes! And I'll show you why exactly we do that, so it makes sense...so when we have squareroot anything it means this \[\huge \sqrt{x} \implies x^{1/2}\] and notice if we square it we get 2/2 hence x^1 :), so squaring both sides would be the proper thing to do!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Alright so we should have what now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Add 3 to both sides?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434494236543:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, subtract 3 I meant

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes :), and our answer will be? :D

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes!! dw:1434494432642:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok last one, and I'm done. Pleaseeee

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given the expression 5a2b – 13ab + 7a3 – 4b, do the following as instructed below: Write the polynomial in descending order. Classify the polynomial by the number of terms. State the degree of the polynomial.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you friend!! *Huge internet hug*

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok lets do it step by step, descending order just means greatest to least (look at the a's). So go ahead and do that now :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Isn't it greatest to least?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, I made a mistake xD

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Tried to fix it before you saw haha, but nice catch!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Good! Now lets state the terms, and figure out what kind it is!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, but I think they might want you to say quadrinomial (meaning 4)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about the degree?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1degree is the highest number of the variables, so we have to sum up the variables for the highest degree, can you figure out which one? :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup, and that's it!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:( Thank you so much for all your help! You were probably the nicest tutor on here I've met so far!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Haha, thanks and your welcome :)
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