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anonymous
 one year ago
The value of y varies directly with x2, and y = 64 when x = 4.
What is the value of y when x = 6?
anonymous
 one year ago
The value of y varies directly with x2, and y = 64 when x = 4. What is the value of y when x = 6?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if that x2 stands for \(x^2\), then: \[y=Ax^2\] where \(A\) is some constant, if you plug \(y=64\) for \(x=4\) you can find the value of \(A\) and then plug \(x=6\) and see what you get for \(y\)...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06^2 would make it 36 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that woul be the case \(A=1\)... you can et the value for \(A\) from: \[64=A\times 4^2\] find that and then calculate \(y=A\times 6^2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the problem says: "The value of y varies directly with x^2, and y = 64 when x = 4" so y must equal "something" times x^2, i called that something A

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im sorry im the worst XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no problem, just keep asking until you understand ! what did you get for A ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well 64/4 is 16 so i multiplied 36 by 16 to get 576

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0note that \(A=\frac{64}{4^2}\) dont forget the square!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont remember how to do that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well \(4^2=16\) so \(A=\frac{64}{16}=4\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0:) that is what i get... good work!
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