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anonymous

  • one year ago

WILL MEDAL AND FAN!! Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.

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  1. anonymous
    • one year ago
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    @Nnesha

  2. anonymous
    • one year ago
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    @mathstudent55

  3. jim_thompson5910
    • one year ago
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    |dw:1434496464182:dw|

  4. anonymous
    • one year ago
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    Yes

  5. jim_thompson5910
    • one year ago
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    We can multiply numbers or algebraic expressions in any order we want so that allows us to pull the 4 out |dw:1434496503786:dw|

  6. jim_thompson5910
    • one year ago
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    |dw:1434496519887:dw|

  7. jim_thompson5910
    • one year ago
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    |dw:1434496533992:dw|

  8. jim_thompson5910
    • one year ago
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    so we now have |dw:1434496572334:dw|

  9. jim_thompson5910
    • one year ago
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    |dw:1434496596197:dw|

  10. anonymous
    • one year ago
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    x^2/1

  11. jim_thompson5910
    • one year ago
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    the square root undoes the squaring similar to how division undoes multiplication or subtraction undoes addition

  12. jim_thompson5910
    • one year ago
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    |dw:1434496685905:dw|

  13. jim_thompson5910
    • one year ago
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    so |dw:1434496718316:dw|

  14. jim_thompson5910
    • one year ago
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    consequently |dw:1434496749847:dw|

  15. anonymous
    • one year ago
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    Ahhhh. I understand!

  16. jim_thompson5910
    • one year ago
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    I'm glad it's making sense

  17. anonymous
    • one year ago
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    Rewrite in simplest radical form 1/x^-3/6

  18. anonymous
    • one year ago
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    @jim_thompson5910 I have the answer, I would kjust like for you to check it

  19. jim_thompson5910
    • one year ago
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    can you draw out the problem?

  20. anonymous
    • one year ago
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    I can't draw a -3

  21. anonymous
    • one year ago
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    It's suppose to be -3/6

  22. jim_thompson5910
    • one year ago
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    is it this? |dw:1434497070307:dw|

  23. jim_thompson5910
    • one year ago
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    ok what answer did you get?

  24. jim_thompson5910
    • one year ago
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    correct |dw:1434497475680:dw|

  25. anonymous
    • one year ago
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    Yup that's what I got :)

  26. anonymous
    • one year ago
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    Thank you for all your help friend!

  27. jim_thompson5910
    • one year ago
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    you're welcome

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