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anonymous

  • one year ago

A 1000 kg aircraft going 25 m/s collides with a 1500 kg aircraft that is parked and they stick together after the collision and are going 10 m/s after the collision. If they skid for 5.5seconds before stopping, how far did they skid? Hint: Are the aircraft moving at a constant velocity after the collision or do they experience an acceleration?

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  1. anonymous
    • one year ago
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    so, after the collision we have a big mass of metal with a speed of 10m/s, if it skids and then stops there should be an acceleration (in this case it should point against the velocity), so the starting velocity is \(v_0=10m/s\) and, if we consider a constant acceleration we can use this equations for velocity and position: \(v=v_0+at\) \((1)\) \(x=v_0t+\frac{1}{2}at^2\) \((2)\) to find when and where the planes stop we must set \(v=0\), and solve for \(t\) and \(x\) Give it a try!

  2. anonymous
    • one year ago
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    so if i'm solving for t and setting v to 0. T = -10/a

  3. anonymous
    • one year ago
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    yes... and you can plug that in eq(2) replacing \(t\) by \(\frac{-10}{a}\) and solving that for a :)

  4. anonymous
    • one year ago
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    is the answer 75 m o-o

  5. anonymous
    • one year ago
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    i get x=27.5m sorry i forgot the time was given in the problem! we need to use t=5.5 sec so a=-1.81m/s^2 please check your calculations

  6. anonymous
    • one year ago
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    Ok i got the same answer as you ! thankyou !! :D

  7. anonymous
    • one year ago
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    great! good work! :)

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