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vera_ewing
 one year ago
How do you solve this?
vera_ewing
 one year ago
How do you solve this?

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3They provided the definition of \(\Large \boxed{x}\) \[\Large \boxed{x} = \frac{x+3}{x1}\] subtract 1 from both sides to get \[\Large \boxed{x}1 = \frac{x+3}{x1}1\] now simplify the right hand side

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Wait why do I subtract 1 from both sides?!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3because they want to know what \(\large \boxed{x}1\) is equivalent to

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1So we just put a 1 on both sides? That makes no sense...

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3you start off with \(\large \boxed{x}\) and do that operation to get \(\large \boxed{x}1\)

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1But there is no 1 originally. Where did it come from?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3maybe it might make more sense if y = 2x was given to you if that's the case, then you would subtract 1 from both sides to get y1 = 2x1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm doing that operation of subtract 1 from both sides to turn \(\large \boxed{x}\) into \(\large \boxed{x}1\) basically it's like turning y into y1

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1I'm so sorry, but why are we allowed to subtract 1 from both sides? There is no 1 on either side of the equation....

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3This is what the full step by step picture looks like \[\Large \boxed{x} = \frac{x+3}{x1}\] \[\Large \boxed{x}1 = \frac{x+3}{x1}1\] \[\Large \boxed{x}1 = \frac{x+3}{x1}1*\frac{x1}{x1}\] \[\Large \boxed{x}1 = \frac{x+3}{x1}\frac{x1}{x1}\] \[\Large \boxed{x}1 = \frac{x+3(x1)}{x1}\] \[\Large \boxed{x}1 = \frac{x+3x+1}{x1}\] \[\Large \boxed{x}1 = \frac{4}{x1}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm using the subtraction property of equality if a = b, then ac = bc

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Ohh okay. And why is there a box around the x on the left?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3because that's how they set up the notation in the problem

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Does it mean anything?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3it's just their fancy way of defining a function

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3they could have easily said "let y = ..." or "let f(x) = ..."

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3why they chose a box, who knows

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Okay. Can you please give me a similar problem to solve?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1I need to be able to do these on my own.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3ok what is \[\Large \boxed{x} +2x\] equivalent to? (same function from the previous problem)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3replace the box x with what it is equal to then simplify

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3box x was equal to (x+3)/(x1)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3so saying \[\Large \boxed{x}+2x\]is the same as saying (x+3)/(x1) + 2x. Simplify from here

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1What would the first step be?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3you need to get the denominators the same

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.32x = 2x/1 has a denominator of 1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3how can you transform that 1 into (x1)

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1So (x+3)/(x1) + 2x/1 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3how can you get 2x/1 to have a denominator of x1

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Multiply 1 on both sides?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3why not multiply top and bottom by (x1) ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3why not multiply top and bottom of 2x/1 by (x1) ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3you might be mixing up + and =

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Show me what that step would look like please.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434499487201:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434499531547:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434499550135:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434499580374:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'll let you finish

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.1Hold on, this all makes so much sense, but I just don't understand what property lets us multiply (x1) on the top and bottom.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm essentially multiplying by 1 (x1)/(x1) = 1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1434499775976:dw